Question

我有3张桌子：

link_art_a

link_art_b

link_art_c

我现在想在一边搜索“ car ”和此输出。

表格几乎相同，我需要的字段：

id, name , mod_name , picture , hits.

该字段位于所需位置，以逗号分隔，例如：

Car , truck , SUV , bike

字段：“tag”

我已经 FIND_IN_SET 尝试，但我总是收到数据库中的所有条目，而不是“汽车”。

到目前为止我尝试过：

SELECT id, name, mod_name, picture, hits from link_art_a 
    UNION ALL
    SELECT id, name, mod_name, picture, hits from link_art_b 
    UNION ALL
    SELECT id, name, mod_name, picture, hits from link_art_c 
    where   
    find_in_field('Car', tag) > 0 order by name asc

有没有人知道我如何得到我想要的结果？

编辑：您好，

问题在于我得到所有记录，包括那些不包含所需单词的记录，例如“car”。

MySQL Dump：

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET AUTOCOMMIT = 0;
START TRANSACTION;
SET time_zone = "+00:00";

CREATE TABLE `link_art_a` (
  `id` bigint(20) NOT NULL,
  `name` varchar(100) NOT NULL,
  `mod_name` varchar(200) NOT NULL,
  `picture` varchar(100) NOT NULL,
  `hits` bigint(20) NOT NULL,
  `tag` varchar(250) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO `link_art_a` (`id`, `name`, `mod_name`, `picture`, `hits`, `tag`) VALUES
(1, 'A8', 'a8.html', 'default.jpg', 251, 'car,sports car,sport,fast'),
(2, 'VW Beetle', 'vw-beetle', 'default.jpg', 269, 'car,fun,slow');

CREATE TABLE `link_art_b` (
  `id` bigint(20) NOT NULL,
  `name` varchar(100) NOT NULL,
  `mod_name` varchar(200) NOT NULL,
  `picture` varchar(100) NOT NULL,
  `hits` bigint(20) NOT NULL,
  `tag` varchar(250) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO `link_art_b` (`id`, `name`, `mod_name`, `picture`, `hits`, `tag`) VALUES
(1, 'Surfboard', 'surfboard', 'default.jpg', 142, 'fun,sport,water'),
(2, 'Sport boat', 'sport-boat', 'default.jog', 163, 'sport,fun,water,fast');

CREATE TABLE `link_art_c` (
  `id` bigint(20) NOT NULL,
  `name` varchar(100) NOT NULL,
  `mod_name` varchar(200) NOT NULL,
  `picture` varchar(100) NOT NULL,
  `hits` bigint(20) NOT NULL,
  `tag` varchar(250) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO `link_art_c` (`id`, `name`, `mod_name`, `picture`, `hits`, `tag`) VALUES
(1, 'Houseboat', 'houseboat', 'default.jog', 144, 'house,boat,water'),
(2, 'Speedboat', 'speedboat', 'default.jpg', 142, 'water,boot,speed,fast');


ALTER TABLE `link_art_a` ADD PRIMARY KEY (`id`), ADD KEY `tag` (`tag`);
ALTER TABLE `link_art_b` ADD PRIMARY KEY (`id`),  ADD KEY `tag` (`tag`);
ALTER TABLE `link_art_c` ADD PRIMARY KEY (`id`),  ADD KEY `tag` (`tag`);


ALTER TABLE `link_art_a`
  MODIFY `id` bigint(20) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=3;
ALTER TABLE `link_art_b`
  MODIFY `id` bigint(20) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=3;
ALTER TABLE `link_art_c`
  MODIFY `id` bigint(20) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=3;COMMIT;

Answer 1

您的where子句仅适用于最后一个select。

您必须将where添加到所有select语句

像这样：

SELECT id, name, mod_name, picture, hits from link_art_a
where   
find_in_set('Car', tag) > 0 

UNION ALL
SELECT id, name, mod_name, picture, hits from link_art_b 
where   
find_in_set('Car', tag) > 0 

UNION ALL
SELECT id, name, mod_name, picture, hits from link_art_c 
where   
find_in_set('Car', tag) > 0

备注：

在这种情况下，您必须删除order by。

是find_in_set()而不是find_in_field()

或者将其添加到所有人

SELECT id, name, mod_name, picture, hits from ( SELECT id, name, mod_name, picture, hits, tag from link_art_a UNION ALL SELECT id, name, mod_name, picture, hits, tag from link_art_b UNION ALL SELECT id, name, mod_name, picture, hits, tag from link_art_c ) as t1 where find_in_set('Car', t1.tag) > 0 order by t1.name asc

使用field_in_set查找标记超过3个没有加入的表

1 个答案: