Question

我想找到两个给定时间戳之间的日期，月份或年份差异，并以标准格式返回。我试过这个，

function cncunix($stamp)
{
   $date = new DateTime("@$stamp");
   echo $date->format('d') . "\n";    
}

// function to convert timestamp
$m = time()+60*60*24;
$n = time();
$y =  $m - $n;
cncunix($y);

Answer 1

$time_a = 86400;
$time_b = 172800;

$total = $time_b - $time_a;

$days = floor($total/86400);

echo "The difference is $days day(s)"

$ days将为您提供向下舍入的天数。例如，2.5将变为2.如果您不想要，则删除楼层功能。

Answer 2

为什么你不使用标准的php func？

<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');

http://php.net/manual/ru/datetime.diff.php

Answer 3

这很简单：

<?php

$m = time()+60*60*24;
$n = time();

$a = new DateTime();
$a->setTimestamp($m);
$b = new DateTime();
$b->setTimestamp($n);

echo $diff = $a->diff($b)->format("%a");

这是Eval

如何找到两个时间戳和两者之间的差异？以标准格式返回

3 个答案: