以下是couchbase中的示例文档(userdetails)。
{
"friends": [
{
"company": "microsoft",
"firstname": "criss",
"lastname": "angel"
},
{
"company": "google",
"firstname": "captain",
"lastname": "america"
}
]}
基于"公司",我想更改"名字"和"姓氏"
N1ql查询(更新单个参数(名字))
update default use keys "userdetails" set a.firstname="xyz" for a in friends when a.company="microsoft" end returning friends
以上查询效果很好。
但我在写查询更新两个参数(名字,姓氏)
N1ql查询(更新两个参数)
update default use keys "userdetails" set a.firstname="abc",a.lastname="xyz" for a in friends when a.company="microsoft" end returning friends
以上查询,仅更新"姓氏"。
输出
{
"friends": [
{
"company": "microsoft",
"firstname": "criss",
"lastname": "xyz"
},
{
"company": "google",
"firstname": "captain",
"lastname": "america"
}
]}
答案 0 :(得分:2)
每个SET术语都是独立的,因此您可以执行以下操作:
UPDATE default
USE KEYS "userdetails"
SET a.firstname="abc" FOR a IN friends WHEN a.company="microsoft" END,
a.lastname="xyz" FOR a IN friends WHEN a.company="microsoft" END
RETURNING friends;
要回答您的评论,以下两种形式可避免双循环。您可以使用实际数据进行测量,以查看哪种形式可以提供最佳性能。
UPDATE default
USE KEYS "userdetails"
SET friends[i] = {"firstname":"abc", "lastname":"xyz", "company":"microsoft"} FOR i : a IN friends WHEN a.company="microsoft" END
RETURNING friends;
UPDATE default
USE KEYS "userdetails"
SET friends[i] = OBJECT_PUT(OBJECT_PUT(a, "firstname", "abc"), "lastname", "xyz") FOR i : a IN friends WHEN a.company="microsoft" END
RETURNING friends;