我在播放连接到按钮/ IBAction的声音时遇到了一些麻烦。
当我在Xcode中为iOS做同样的事情时,它完美无缺。但是,当我为OS X执行此操作时,它不起作用。有什么想法吗?
import Cocoa
import AVFoundation
class ViewController: NSViewController, NSSpeechRecognizerDelegate {
var pingAudioPlayer : AVAudioPlayer?
var sr = NSSpeechRecognizer()
@IBOutlet var output: NSTextView?
func playPing(){
let pingSound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("ping", ofType: "mp3")!)
pingAudioPlayer = AVAudioPlayer(contentsOfURL: pingSound, error: nil)
pingAudioPlayer!.prepareToPlay()
pingAudioPlayer!.currentTime = 0
pingAudioPlayer!.play()
}
@IBAction func soundTest(sender: AnyObject) {
playPing()
}
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
sr.delegate = self
sr.commands = ["Ping", "Ping Mac"]
sr.startListening()
}
func speechRecognizer(sender: NSSpeechRecognizer, didRecognizeCommand command: AnyObject?) {
output!.string! += "\(command)\n"
playPing()
}
override var representedObject: AnyObject? {
didSet {
// Update the view, if already loaded.
}
}
}
答案 0 :(得分:0)
主要问题是speechRecognizer
方法,它不是正确的签名。
import AVFoundation
class ViewController: NSViewController, NSSpeechRecognizerDelegate {
var pingAudioPlayer : AVAudioPlayer?
var sr = NSSpeechRecognizer()
@IBOutlet var output: NSTextView?
func playPing(){
let pingSound = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource("ping", ofType: "mp3")!)
pingAudioPlayer = try? AVAudioPlayer(contentsOfURL: pingSound)
pingAudioPlayer?.prepareToPlay()
pingAudioPlayer?.currentTime = 0
pingAudioPlayer?.play()
}
@IBAction func soundTest(sender: AnyObject) {
playPing()
}
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
sr?.delegate = self
sr?.commands = ["Ping", "Ping Mac"]
sr?.startListening()
}
func speechRecognizer(sender: NSSpeechRecognizer, didRecognizeCommand command: String) {
output?.string! += "\(command)\n"
playPing()
}
}