Question

我有可自定义的对象类我想序列化：

public partial class CustomObject
{               
    public List<CustomProperty> Properties;
}

public class CustomProperty
{              
    public object Value;                
    [XmlAttribute]
    public string Name;
}

// some class to be used as a value for CustomProperty
public class Person
{
  public string Name;
  public string Surname;
  public string Photo;
  [XmlAttribute]
  public int Age;
}

目前，XML序列化输出如下所示：

<CustomObject>
  <Properties>
    <CustomProperty Name="Employer">
      <Value p6:type="Person" xmlns:p6="http://www.w3.org/2001/XMLSchema-instance" Age="30">
        <Name>John</Name>
        <Surname>Doe</Surname>
        <Photo>photos/John.jpg</Photo>
      </Value>
    </CustomProperty>
    <CustomProperty Name="Desc">
      <Value xmlns:q1="http://www.w3.org/2001/XMLSchema" p7:type="q1:string" xmlns:p7="http://www.w3.org/2001/XMLSchema-instance">some text</Value>
    </CustomProperty>
  </Properties>
</CustomObject>

首先，我想删除命名空间和所有噪音。

最终结果应如下所示：

<CustomObject>
  <Properties>
    <CustomProperty Name="Employer">
      <Person Age="30">
        <Name>John</Name>
        <Surname>Doe</Surname>
        <Photo>photos/John.jpg</Photo>
      </Person>
    </CustomProperty>
    <CustomProperty Name="Desc">
      <string>some text</string>
    </CustomProperty>
  </Properties>
</CustomObject>

或者这个：

<CustomObject>
  <Properties>
    <Person Name="Employer" Age="30">
      <Name>John</Name>
      <Surname>Doe</Surname>
      <Photo>photos/John.jpg</Photo>
    </Person>
    <string Name="Desc">
      some text
    </string>
  </Properties>
</CustomObject>

如何让XmlSerializer像这样输出它？

Answer 1

查看XmlElement属性 - 这可能至少可以部分解决您的问题。来自MSDN：

public class Things {
    [XmlElement(DataType = typeof(string)),
    XmlElement(DataType = typeof(int))]
    public object[] StringsAndInts;
 }

将产生

 <Things>
    <string>Hello</string>
    <int>999</int>
    <string>World</string>
 </Things>

Answer 2

您还可以指定元素名称以确保正确处理类型：

[System.Xml.Serialization.XmlElementAttribute("files", typeof(Files))]
[System.Xml.Serialization.XmlElementAttribute("metrics", typeof(Metrics))]
public object[] Items { get; set; }

Answer 3

您可以删除

之类的命名空间

            StringBuilder sb = new StringBuilder();
            XmlWriter writer = XmlWriter.Create(sb);
            XmlSerializer serializer = new XmlSerializer(typeof(WSOpenShipments), myns);
            var ns = new XmlSerializerNamespaces();
            ns.Add(string.Empty, "");
            serializer.Serialize(writer, OS, ns);
            xmlString = sb.ToString();

使用这个 - ns.Add（string.Empty，“”）;

如何自定义Object的XML序列化输出？

3 个答案: