Question

#!/bin/bash
prev='placeholder'
filename='mkDir.txt'
echo "Starting mkDir script using mkDir.txt."
while IFS=' ' read line || [[ -n "$line" ]]; do
    echo "creating dir : $line"
    if [[ ${line:0:1} == [[:space:]] ]]
    then
        cd $prev
        mkdir $line
        cd '..'
    else
        mkdir $line
    fi
    prev=$line
done < $filename

这是我目前的脚本。但它不会像我想要的那样创建子目录。我理想的文本文件如下所示：

tester
    test
test2

标签/空格应该表明这是一个子目录。我怎样才能让它发挥作用？

Answer 1

就个人而言，我宁愿使用AWK程序从输入文件生成bash脚本，然后运行bash脚本：

#!/bin/awk
# WARNING: this example assumes there are is no whitespace in the directory names!
BEGIN { parentdir = "." }
/^[[:space:]]*$/ { next }
/^[[:space:]]/ { print "mkdir " parentdir "/" $1; next }
{ parentdir = $1; print "mkdir " parentdir }

这样调用AWK：awk -f file-with-code-from-above mkDir.txt

内容为

的文件mkDir.txt

 subdir
dir1
 subdir
dir2
 subdir

会产生输出

mkdir ./subdir
mkdir dir1
mkdir dir1/subdir
mkdir dir2
mkdir dir2/subdir

Answer 2

使用Bash arrays

#!/bin/bash -

function join { local IFS="$1"; shift; echo "$*"; }

branch=()
while IFS=/ read -r -a parts; do
    level=${#parts[@]}
    branch=( ${branch[@]:0:$level} )

    (( --level ))

    branch[$level]="${parts[$level]}"

    mkdir -p $(join / "${branch[@]}")
done < <(sed -e 's~\t~/~g' input.txt)

join函数使用$2 .. $* separator

$1

sed命令用input.txt file
sed命令的输出通过process substitution

while

IFS是field separator
${branch[@]:0:$level}从branch到0提取$level - 1个数组项目

在PHP中

<?php
$branch = [];
$fp = fopen('php://stdin', 'r');

while ($line = fgets($fp)) {
  $parts = explode("\t", $line);
  $level = count($parts);
  $branch = array_slice($branch, 0, $level);
  $branch[$level - 1] = trim($parts[$level - 1]);

  mkdir(implode('/', $branch), 0755, true);
}

fclose($fp);

用法：

php script.php < input.txt

如何使用文本文件中的子目录创建多个目录？

2 个答案: