Question

我想将所选复选框中的所有值放入其自己的PHP变量中。这些复选框的值由PHP / SQL生成。必须在下拉框下方的简单<div>中显示相同的变量。我也在使用Bootstrap Multiselect插件。但我从null测试中得到var_dump()值。

这是我到目前为止所尝试的内容：

<form id="menu1" method="POST" action="index.php">
    <h2>Area Code</h2>
    <select id="multi-select1" name="multi_select1[]" multiple="multiple">
        <?php
            //The query asking from our database
            $areaCodeSQL = "SELECT ac.Number AS `AreaCode`, ac.Name AS `AreaName`
                            FROM `AreaCodes` ac";                                                               //SQL query: From the table 'AreaCodes' select 'Number' and put into 'AreaCode', select Name and put into 'AreaName'

            $areaCodeResults = $conn->query($areaCodeSQL);                                                      // put results of SQL query into this variable

            if ($areaCodeResults->num_rows > 0) {                                                               // if num_rows(from $results) is greater than 0, then do this:
                // output data of each row
                            foreach($areaCodeResults as $areaCodeResult)                                        //for each item in $areCodeResults do this:
                                {
                                    $areaNameAndCode =  $areaCodeResult['AreaCode'] ." ". $areaCodeResult['AreaName'];  //get AreaCode and AreaName from query result and concat them
                                    $areaName = $areaCodeResult['AreaName'];                                    // get AreaName
                                    $areaCode = $areaCodeResult['AreaCode'];                                    //get AreaCode

                                    ?><option class="menuoption1" name="menuAreaCode" value="<?php echo $areaCode ?>"  ><?php echo $areaNameAndCode; ?></option><?php  //Create this option element populated with query result variables
                                }
            } 
            $result = $_POST['multi_select1'];                   
        ?>
    </select>   
</form>
<div id="showResults1"><?php var_dump($result) ?></div>

然而，我可以通过使用jQuery完成我想要做的事情，但我希望能够将这些值发送到数据库，我的导师希望它们在PHP变量中。我知道我可以使用AJAX将它们发送到我的数据库，但这是我的导师想要的。我不知道我是否走在正确的轨道上，所以非常感谢任何帮助

Answer 1

在第一次运行时，您不会从该POST变量中读取任何内容，因此请对其进行处理。试试这段代码，它应该可以工作：

<form id="menu1" method="POST">
    <h2>Area Code</h2>
    <select id="multi-select1" name="multi_select1[]" multiple="multiple" action="index.php">
        <?php
            //The query asking from our database
            $areaCodeSQL = "SELECT ac.Number AS `AreaCode`, ac.Name AS `AreaName`FROM `AreaCodes` ac";                                                               //SQL query: From the table 'AreaCodes' select 'Number' and put into 'AreaCode', select Name and put into 'AreaName'
            $areaCodeResults = $conn->query($areaCodeSQL);                                                      // put results of SQL query into this variable

            if ($areaCodeResults->num_rows > 0) {                                                               // if num_rows(from $results) is greater than 0, then do this:
            // output data of each row
                foreach($areaCodeResults as $areaCodeResult) { ?>
                    <option class="menuoption1" name="menuAreaCode" value="<?php echo $areaCodeResult['AreaCode'] ?>"  ><?php echo $areaCodeResult['AreaCode'] ." ". $areaCodeResult['AreaName']; ?></option>
            <?php } ?>
    </select>   
    <input type="submit" value="Send" />
</form>
<div id="showResults1">
    <?php 
    $result = isset($_POST['multi_select1']) ? $_POST['multi_select1'] : [];
    var_dump($result);
    ?>
</div>

将选中的复选框添加到PHP变量中，然后我可以直接在

1 个答案: