我注意到这两个表达式返回不同的长度(检查控制台):
var cssSelector = $('#target').siblings('table > tbody > tr > td').length; // returns 0
var jQuerySelector = $('#target').siblings('table').children('tbody').children('tr').children('td').length; // returns 1
console.log('cssSelector: ' + cssSelector);
console.log('jQuerySelector: ' + jQuerySelector);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<div id="target">Target</div>
<table>
<tbody>
<tr><td>Cell</td></tr>
</tbody>
</table>
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我希望他们都选择相同的元素,因此他们会返回相同的结果。
答案 0 :(得分:1)
.siblings('table > tbody > tr > td')
匹配td
个元素。你可以说,因为选择器的主题是td
。由于#target
的兄弟是table
,而不是td
,因此不会与任何内容匹配。
.siblings('table')
匹配table
个元素。然后,您会跟进一系列.children()
次调用,这些调用会深入到表td
后代,从而产生成功的匹配。
答案 1 :(得分:1)
因为table
是#target
的兄弟,并且您说td
是您var cssSelector
中的兄弟姐妹,这是不正确的,因为{{1} }是td
的孩子。
table
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var cssSelector = $('#target').siblings('table').length; // returns 1
var jQuerySelector = $('#target').siblings('table').children('tbody').children('tr').children('td').length; // returns 1
console.log('cssSelector: ' + cssSelector);
console.log('jQuerySelector: ' + jQuerySelector);
&#13;
答案 2 :(得分:0)
此处java.lang.NullPointerException
at org.activiti.engine.impl.persistence.entity.ExecutionEntity.performOperationSync(ExecutionEntity.java:636)
at org.activiti.engine.impl.persistence.entity.ExecutionEntity.performOperation(ExecutionEntity.java:629)
at org.activiti.engine.impl.persistence.entity.ExecutionEntity.take(ExecutionEntity.java:453)
at org.activiti.engine.impl.persistence.entity.ExecutionEntity.take(ExecutionEntity.java:431)
at org.activiti.engine.impl.bpmn.behavior.BpmnActivityBehavior.performOutgoingBehavior(BpmnActivityBehavior.java:140)
at org.activiti.engine.impl.bpmn.behavior.BpmnActivityBehavior.performDefaultOutgoingBehavior(BpmnActivityBehavior.java:66)
at org.activiti.engine.impl.bpmn.behavior.FlowNodeActivityBehavior.leave(FlowNodeActivityBehavior.java:44)
at org.activiti.engine.impl.bpmn.behavior.AbstractBpmnActivityBehavior.leave(AbstractBpmnActivityBehavior.java:47)
提供的表格是$('#target').siblings('table')
的兄弟,然后您需要通过#target
.find("tbody > tr > td")
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var cssSelector = $('#target').siblings('table').find("tbody > tr > td").length; // returns 0
var jQuerySelector = $('#target').siblings('table').children('tbody').children('tr').children('td').length; // returns 1
console.log(cssSelector);
console.log(jQuerySelector);
&#13;