XNA按钮单击未触发

时间:2016-05-10 11:00:55

标签: c# button xna click

我创建了一个按钮类,我在主游戏类中调用它。但它并没有解雇。实际上我想点击鼠标左键上的Button类里面的Update方法。我通过Debug.WriteLine检查所有鼠标事件,一切看起来都正常。可能有什么不对?

GameBase类

public class GameBase : Microsoft.Xna.Framework.Game
{
    GraphicsDeviceManager graphics;
    Button btn;

    public GameBase()
    {
        graphics = new GraphicsDeviceManager(this);
        Content.RootDirectory = "Content";
        IsMouseVisible = true;
        graphics.PreferredBackBufferWidth = 600;
        graphics.PreferredBackBufferHeight = 400;
    }
    protected override void Initialize()
    {
        base.Initialize();
    }
    protected override void LoadContent()
    {
        spriteBatch = new SpriteBatch(GraphicsDevice);
        btn = new Button(Content.Load<Texture2D>("Sprites/Button"), new Vector2(150, 150));
    }
    protected override void UnloadContent()
    {
    }
    protected override void Update(GameTime gameTime)
    {
        if (GamePad.GetState(PlayerIndex.One).Buttons.Back == ButtonState.Pressed)
            this.Exit();
        MouseState mouse = Mouse.GetState();
        //Debug.WriteLine(mouse);

        if (btn.Clicked == true)
        {
            Debug.WriteLine("Clicked");
            currentState = GameState.Playing;
            btn.Update(mouse);
        }
        base.Update(gameTime);
    }
    protected override void Draw(GameTime gameTime)
    {
        GraphicsDevice.Clear(Color.CornflowerBlue);

        spriteBatch.Begin();
        spriteBatch.Draw(Content.Load<Texture2D>("Sprites/StartBg"), new Rectangle(0, 0, _screenWidth, _screenHeight), Color.White);
        btn.Draw(spriteBatch);
        spriteBatch.End();
        base.Draw(gameTime);
    }
}

按钮类

public class Button
{
    public bool Clicked { get; set; }
    private Texture2D _image;
    private Rectangle _rectangle, _mouseRectangle;
    private Vector2 _coordinate;
    private Color _color;
    private bool _down;

    public Button(Texture2D image, Vector2 coordinate)
    {
        _image = image;
        _coordinate = coordinate;
    }
    public void Update(MouseState mouse)
    {
        mouse = Mouse.GetState();
        _rectangle = new Rectangle((int)_coordinate.X, (int)_coordinate.Y, _image.Width, _image.Height);
        _mouseRectangle = new Rectangle(mouse.X, mouse.Y, 1, 1);

        if (_mouseRectangle.Intersects(_rectangle))
        {
            if (_color.A == 255)
                _down = false;
            if (_color.A == 0)
                _down = true;
            if (_down)
            {
                _color.A += 3;
            }
            else
            {
                _color.A -= 3;
            }
            if (mouse.LeftButton == ButtonState.Pressed)
            {
                Clicked = true;
            }
            else if (_color.A < 255)
            {
                _color.A += 3;
                Clicked = false;
            }
        }
    }
    public void Draw(SpriteBatch spriteBatch)
    {
        spriteBatch.Draw(_image, _coordinate, Color.White);
    }
}

1 个答案:

答案 0 :(得分:0)

你的逻辑有点搞砸了。在一个句子中,您的代码是:如果单击了按钮,请执行更新,检查是否单击了该按钮。这样您就永远无法更新按钮。

尝试Update功能的此修改版本:

protected override void Update(GameTime gameTime)
{
    if (GamePad.GetState(PlayerIndex.One).Buttons.Back == ButtonState.Pressed)
        this.Exit();
    MouseState mouse = Mouse.GetState();
    //Debug.WriteLine(mouse);

    btn.Update(mouse);
    if (btn.Clicked == true)
    {
        Debug.WriteLine("Clicked");
        currentState = GameState.Playing;
    }
    base.Update(gameTime);
}

句子中的这段代码意味着:更新按钮,检查按钮是否被点击,然后,如果单击按钮,则在调试中单击“Clicked”并将gameState设置为Play。

编辑1:
此外,我没有看到颜色应该与点击有关。 在按钮更新方法,我担心这个代码的和平

        if (mouse.LeftButton == ButtonState.Pressed)
        {
            Clicked = true;
        }
        else if (_color.A < 255)
        {
            _color.A += 3;
            Clicked = false;
        }

我宁愿放这样的东西:

        if (mouse.LeftButton == ButtonState.Pressed)
        {
            Clicked = true;
        }
        else
        {
            if (_color.A < 255)
                _color.A += 3;
            Clicked = false;
        }

这样将这段代码放在一个句子中就更简单了,这种简单性使它无论_color.A是什么值都可以工作,但_color.A也会在你需要的时候更新。