Question

我正在使用django-filter。我有过滤类：

class ProductFilter(django_filters.FilterSet):
    def __init__(self, attribute=None, *args, **kwargs):
        super(ProductFilter, self).__init__(*args, **kwargs)
        #do stuff with attribute

和我的观点：

from django_filters.views import FilterView
class ProductListView(FilterView):
        model = Product
        ....
        filterset_class = ProductFilter

如何将参数传递给ProductFilter __init__函数？ filterset_class = ProductFilter(attribute='width')不起作用。

Answer 1

您可以尝试覆盖get_filterset_kwargs方法：

class ProductListView(FilterView):
    model = Product
    ...
    filterset_class = ProductFilter

    def get_filterset_kwargs(self, filterset_class)
        kwargs = super(ProductListView, self).get_filterset_kwargs(filterset_class)
        kwargs['attribute'] = 'width'
        return kwargs

在FilterSet课程中，您可以从kwargs中弹出属性：

class ProductFilter(django_filters.FilterSet):
    def __init__(self, **kwargs):
        attribute = kwargs.pop['attribute']
        super(ProductFilter, self).__init__(**kwargs)

或明确地将其包含在签名中。

class ProductFilter(django_filters.FilterSet):
    def __init__(self, attribute=None, **kwargs):
        super(ProductFilter, self).__init__(**kwargs)

django将额外的参数传递给filterset_class

1 个答案: