Question

我是Android的编程新手 - 请耐心等待。

我正在使用OKHttp构建需要网络访问权限的应用。由于我将从我的服务器发出许多类似结构的请求，因此我创建了一个处理所有与网络相关的任务的类，因为我喜欢将事情分开。

我工作的一种方法是createNetworkThread课程内的NetworkManager。这个特殊的方法有三个参数：

Context context, final String requestURI, final RequestBody formParameters

我需要帮助的是如何返回从此方法收到的数据，以便我可以在调用Activity中使用和操作它。

以下是有问题的方法：

public void createNetworkThread(Context context, final String requestURI, final RequestBody formParameters) {
    if (!this.isConnected(context)) return;

    Runnable runnable = new Runnable() {
        @Override
        public void run() {
            OkHttpClient client = new OkHttpClient();
            Request request = new Request.Builder().url(requestURI).post(formParameters).build();

            Response response = null;

            // Send login request, get response //

            try {
                response = client.newCall(request).execute();
                String stringResponse = response.body().string();
                JSONObject jsonResponse = new JSONObject(stringResponse);

                Log.d("Net", "Request send and received!");

            } catch (IOException e) {
                Log.d("Net", "Failed");
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }
    };

    Thread thread = new Thread(runnable);
    thread.start();
}

以下是来自活动的电话：

final NetworkManager Net = new NetworkManager(this);

...

final String requestURI = "http://192.168.1.111/videonow.club/apprequest/signup/thread.php";
final RequestBody formVars = new FormBody.Builder().add("email", strEmail).add("password", strPass1).add("first_name", strNameFirst).add("last_name", strNameLast).build();

Net.createNetworkThread(SignupActivity.this, requestURI, formVars);

我需要知道的是如何从方法返回的jsonResponse获取JSON数据（我知道void不允许这样做）所以我可以使用这些数据。

让jsonObject返回会更好，所以我可以使用这样的东西：

SomeType response = Net.createNetworkThread(...);

或者，要在NetworkManager中设置一个类变量，该类变量将由方法设置，因此它将被调用并引用如下：

Net.createNetworkThread(...);
SomeType response = Net.someVariable;

或者是否有更合理的方式来接收这些数据？

我也在调用new OkHttpClient()两次 - 一次在活动中，因此我可以构建requestBody帖子变量，以及NetworkManager类本身。我的直觉告诉我这是多余的......如果是这样，有没有办法让这更有效率？

提前致谢！

Answer 1

您可以将OkHttp与AysncTask一起使用，如下所示：

public class Webservice extends AsyncTask<String, String, UserResponse> {

private String TAG = Webservice.class.getSimpleName();
private static final String ENDPOINT = "YOUR_URL";
private static final Moshi MOSHI = new Moshi.Builder().build();
private static final JsonAdapter<UserResponse> CONTRIBUTORS_JSON_ADAPTER_RESPONSE = MOSHI.adapter(Types.newParameterizedType(UserResponse.class, UserResponse.class));

UserResponse webResponse;
public static final MediaType JSON = MediaType.parse("application/json; charset=utf-8");
String postBody = "postBody\n";

@Override
protected UserResponse doInBackground(String... parmas) {
    OkHttpClient.Builder okHttpClient = new OkHttpClient.Builder();
    Call call = okHttpClient.build().newCall(new Request.Builder()
            .url(ENDPOINT)
            .post(RequestBody.create(JSON, postBody))
            .addHeader("Content-Type", "application/json")
            .build());

    try {
        Response response = call.execute();
        adModelResponse = CONTRIBUTORS_JSON_ADAPTER_RESPONSE.fromJson(response.body().source());

    } catch (IOException e) {
        e.printStackTrace();
    }
    return webResponse;
}

@Override
protected void onPostExecute(UserResponse adModelResponse) {


}
}

然后在这样的Activity调用中：

Webservice webservice = new Webservice();
webservice.execute("YOUR_PARAMETER");

使用的库：

okhttp-3.2.0，moshi-1.1.0，okio-1.8.0

Answer 2

您可以使用回调界面将数据恢复到您的活动中。请考虑以下示例：

public interface JsonResponse {
   onResponseReceived(JSONObject response);
}

然后您的createNetworkThread将如下所示：

public void createNetworkThread(Context context, final String requestURI, final RequestBody formParameters, JsonResponse responseCallback) {
    if (!this.isConnected(context)) return;

    Runnable runnable = new Runnable() {
        @Override
        public void run() {
            OkHttpClient client = new OkHttpClient();
            Request request = new Request.Builder().url(requestURI).post(formParameters).build();

            Response response = null;

            // Send login request, get response //

            try {
                response = client.newCall(request).execute();
                String stringResponse = response.body().string();
                JSONObject jsonResponse = new JSONObject(stringResponse);
                responseCallback.onResponseReceived(jsonResponse); // This line will return to your caller

                Log.d("Net", "Request send and received!");

            } catch (IOException e) {
                Log.d("Net", "Failed");
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }
    };

    Thread thread = new Thread(runnable);
    thread.start();
}

最后来电者：

Net.createNetworkThread(SignupActivity.this, requestURI, formVars, new JsonResponse() {
            @Override
            public void onResponseReceived(JSONObject response) {
                // Do stuff in your activity
                // eventually use runOnUiThread for your UI operations 
            }
        });

Answer 3

创建NetworkManager Abstract并添加一个抽象方法public abstract void onResult(JSONObject response);并覆盖此方法，如

final NetworkManager Net = new NetworkManager(this){
@Override
public void onResult(JSONObject response){
//do whatever you want here
}
};

从createNetworkThread完成后，将此方法称为

.....
response = client.newCall(request).execute();
                String stringResponse = response.body().string();
                JSONObject jsonResponse = new JSONObject(stringResponse);
onResult(jsonResponse);
......

创建网络线程作为方法

3 个答案: