Question

我有一个字符串

1,2,3|5

与[{1}}分割后我有

|，1,2,3

现在我想将5转换为1,2,3。我怎样才能做到这一点？

以下是我的查询

INT

我想在

中使用它

Declare @tmpReferContentRule = "1,2,3|5"
SELECT items 
FROM splitbystring(@tmpReferContentRule,'|') 
WHERE id = 1

_{SELECT name
FROM tmptable
WHERE id in(SELECT items FROM splitbystring(@tmpReferContentRule,'|'))
是整数类型}

以上查询引发错误

1,2,3无法转换为int。

请提出解决方案。

Answer 1

你可以试试这个 -

Declare @tmpReferContentRule varchar(20) = '1,2,3|5'

;with cte
AS
(
    SELECT items as subitem from dbo.splitbystring(@tmpReferContentRule,'|')
)
SELECT name FROM tmptable WHERE id IN 
(
    SELECT t.items FROM cte
    CROSS APPLY (SELECT * from dbo.splitbystring (subitem,',')) t
)

Answer 2

试试这个方法

select name from tmptable as t1 inner join (@tmpReferContentRule,'|') as t2 on 
','+t2.items+',' like '%,'+cast(t1.id as varchar(10)+',%' 
where t2.id=1

Answer 3

您可以借助xml：

将该字符串转换为表格

DECLARE @string nvarchar(10) = '1,2,3|5',
        @xml xml

SELECT @xml = CAST('<r><a>' + REPLACE(REPLACE(@string,',','</a><a>'),'|','</a><b>') +'</b></r>'  as xml)

SELECT  t.v.value('.','int') as id
FROM @xml.nodes('/r/a') as t(v)

输出：

id
1
2
3

Answer 4

我发现你一直在使用分割字符串功能我有一个类似的split string sql function，我在你的脚本中使用了两次

Declare @tmpReferContentRule varchar(max) = '1,2,3|5'

SELECT *
FROM Table1 t
inner join (
    select 
        s2.val 
    from dbo.Split(@tmpReferContentRule,'|') s1
    cross apply dbo.Split(s1.val,',') s2
    WHERE 
        s1.id = 1
) s on t.id = s.val

SQL SERVER 2014 - Split String＆amp;转换为INT

4 个答案: