Question

我有一个从DB获得的多维数组。 Array每小时都有一些视图，这些视图作为视图记录在数据库中，它看起来像这样：

array:11 [▼
    0 => array:2 [▼
         "hour" => 0
         "views" => 1
         ]
    1 => array:2 [▼
         "hour" => 1
         "views" => 1
         ]
    2 => array:2 [▼
         "hour" => 4
         "views" => 1
         ]
    ...and so on
    ]

我需要创建一个包含2个小时范围的视图数量的新数组。因此，例如从上面显示的数组中，我想得到一个数组，其中0到2之间的时间视图数量，2和2-4，在这种情况下将为0，依此类推。

Answer 1

你可以在Mysql查询中执行：

select floor(hour/2) range, sum(views) sum 
   from thetable 
 group by range

Answer 2

您可以使用foreach创建新数组。

<?php


$your_array = [0 => [
         "hour" => 0,
         "views" => 4
         ],
    1 => [
         "hour" => 1,
         "views" => 12
         ],
    2 => [
         "hour" => 4,
         "views" => 1
         ],
    3 => [
         "hour" => 2,
         "views" => 9
         ],
    4 => [
         "hour" => 21,
         "views" => 19
         ]
         ];   



foreach ($your_array as $value){
    for($i=0;$i<=22;$i=$i+2){
    $j=$i+2;
    if($value['hour']>=$i && $value['hour']<$j){
        isset($result[$i.'-'.$j])?$result[$i.'-'.$j]+=$value['views']:$result[$i.'-'.$j]=$value['views'];
    }
    }
}

print_r($result);

Answer 3

尝试以下代码。

$arr = [0 => [
         "hour" => 0,
         "views" => 1
         ],
    1 => [
         "hour" => 1,
         "views" => 1
         ],
    2 => [
         "hour" => 4,
         "views" => 1
         ]];    

foreach($arr as $row)
{
    if($row['hour'] >= 0 && $row['hour'] <= 2)
    {
        $newArr['0-2'] = isset($newArr['0-2']) ? ($newArr['0-2'] + 1) : 1;
    }
    if($row['hour'] > 2 && $row['hour'] < 4)
    {
        $newArr['2-4'] = isset($newArr['2-4']) ? ($newArr['2-4'] + 1) : 1;
    }
}
print_r($newArr);

<强>输出

Array
(
    [0-2] => 2
)

PHP-按数字范围将多维数组排序到另一个数组中

3 个答案: