Question

我有这个SELECT语句：

int r =  Random.value*n;

其中显示输出列为十进制数字（例如）62.24837411，我知道我可以将其放入excel并将列格式化为百分比，但我的问题是如何让SQL将其转换为百分比？我已经尝试将十进制（18,2）更改为十进制（4,2）这是我想要的但它只是抛出数学溢出错误？

Answer 1

试试这个：

select  convert(DECIMAL(10,2),column)

精确到2位小数

Answer 2

您将cast放在错误的地方

cast(SUM(CASE WHEN t.clmOutcomeType='Resolved' THEN 1 ELSE 0 END) as decimal(18,2))/cast(Count(t.clmCaseID) as decimal(18,2))*100 as [TotalResolved %],

将CAST放在整个结果中，如下所示：

cast(SUM(CASE WHEN t.clmOutcomeType='Resolved' THEN 1 ELSE 0 END)/cast(Count(t.clmCaseID) as decimal(18,2))*100  as decimal(18,2)) as [TotalResolved %],

Answer 3

AS Arul建议，您需要在整个列计算中使用强制转换函数。

  SELECT
 t.clmUnit,
 t.clmConType,
 Count(t.clmCaseID) TotalCases,
 SUM(CASE WHEN t.clmOutcomeType='Resolved' THEN 1 ELSE 0 END) TotalResolved,
 cast(SUM(CASE WHEN t.clmOutcomeType='Resolved' THEN 1 ELSE 0 END))/Count(t.clmCaseID) * 100  as decimal(18,2)) as [TotalResolved %],
SUM(CASE WHEN t.clmOutcomeType='Unresolved' THEN 1 ELSE 0 END) TotalCaseProgressed,
cast(SUM(CASE WHEN t.clmOutcomeType='Unresolved' THEN 1 ELSE 0 END))/Count(t.clmCaseID) * 100 as decimal(18,2)) as [TotalCaseProgressed %],
SUM(CASE WHEN t.clmOutcomeType='Work In Progress' THEN 1 ELSE 0 END) TotalFurtherConReq,
cast(SUM(CASE WHEN t.clmOutcomeType='Work In Progress' THEN 1 ELSE 0 END))/Count(t.clmCaseID) * 100 as decimal(18,2)) as [TotalFurtherConReq %]

如何将SQL输出修复为两位小数

3 个答案: