Question

我试图使用Boost Python从C ++中的Python函数访问返回的字符串值。

我看到了这个错误：

TypeError: No registered converter was able to produce a C++ rvalue of type std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> > from this Python object of type function

错误有意义，Python数据类型与C ++数据类型不匹配。但我不确定如何解决它。

C ++代码是：

    Py_Initialize();
try {
    boost::python::object main = boost::python::import("__main__");

    boost::python::object global(main.attr("__dict__"));

    boost::python::object result = exec_file("/Users/tomconlin/Documents/495_496_Research/Current_Source_Code/Source_Files/test_hello.py", global, global);

    boost::python::object test_hello = global["get_info"];

    std::string message = boost::python::extract<std::string>(test_hello);

    std::string m = message;
    std::cout << message << std::endl;
    return message;
}
catch (boost::python::error_already_set&) {
    PyErr_Print();
}

Py_Finalize();

std::string error_string = "\nAn Error Occured\n";
return error_string;

Python代码是：

import sys
sys.path.append("/Users/tomconlin/anaconda/lib/python2.7/site-packages")

def get_info():
     version = 2 # API version
     block_io = BlockIo('2c18-7990-8d0d-7511', '7816902248', version)

     credit_card_balance = block_io.get_address_balance(addresses='2Mytv6K7BkiBRuHhnHmVTTc51xyhLRNtDgr')

     #print "Credit Card Balance Type:", type(credit_card_balance)
     address = ""
     for key in credit_card_balance:
         address += str(credit_card_balance[key])

    #print "This is the address:", address
    address = address.split()
    #print address
    print "\n\n"
    return_address = address[12].strip("u',")
    print return_address
    print "\n\n"
    return return_address

def main():
    get_info()

if __name__ == '__main__':
    from block_io import BlockIo
    main()

Answer 1

您可能希望调用该函数并将返回值作为字符串获取，而不是尝试将函数本身转换为字符串。

因此，您可能想要使用：

boost::python::extract<std::string>(test_hello());

而不是：

boost::python::extract<std::string>(test_hello);

这是一个概括性的例子。在hello.py：

def hello_from_python ():
  return 'Hello from Python!'

在example.cc：

#include <iostream>
#include <string>
#include <boost/python.hpp>

namespace py = boost::python;

int main (int argc, char * argv []) {
  // Initialize the Python interpreter.
  Py_Initialize();

  // Add the current directory to the path.
  py::import("sys").attr("path").attr("append")(".");

  // Get the "hello_from_python" function from "hello.py".
  py::object hello_from_python = py::import("hello").attr("hello_from_python");

  // Call the "hello_from_python" and extract the return value as a string.
  std::string return_value = py::extract<std::string>(hello_from_python());

  // Print out the return value.
  std::cout << "Return value: '" << return_value << "'" << std::endl;
}

编译，然后运行程序：

$ ./example
Return value: 'Hello from Python!'

Boost :: Python Extract - 在C ++中访问Python字符串

1 个答案: