Question

我应该创建一个包含名为Person的类的AddressBook。我的程序几乎可以正常工作，除非我添加一个人，它在命令菜单的下一次迭代中不会记住它并且显示全部显示＆＃34;您的地址簿中有0个人。＆＃34 ;我的代码出了什么问题？

#include <iostream>
#include <string>  

using namespace std;

class AddressBook {

public:
    class Person
    {
    public:
        char firstName[15];
        char lastName[15];
        char personID[15];
    };

    Person entries[100];

    unsigned int total;

    AddressBook()
    {
        total = 0;
    }

    void AddPerson()
    {
        cout << "This is entry number " << (total + 1) << " in your address book. " << endl;

        cout << "What shall we put for the first and last name? Limit both to under 15 characters. Example: Bob Smith" << endl;
        cin >> entries[total].firstName >> entries[total].lastName;

        cout << "What is " << entries[total].firstName << " " << entries[total].lastName << "'s ID code?" << endl;
        cin >> entries[total].personID;

        ++total;
        cout << "..." << endl << "Successfully Added." << endl;
    };

    void DisplayPerson(int i)
    {
        cout << "Entry " << i + 1 << ": " << endl;
        cout << "FIRST NAME: " << entries[i].firstName << endl;
        cout << "LAST NAME: " << entries[i].lastName << endl;
        cout << "ID: " << entries[i].personID << endl;
    };

    void DisplayEveryone()
    {
        cout << "You have " << total << " People in your address book." << endl;

        for (int i = 0; i < total; ++i)
            DisplayPerson(i);
    };


    void SearchPerson()
    {
        char lastname[32];
        cout << "Please enter the last name of the person you wish to find." << endl;
        cin >> lastname;

        for (int i = 0; i < total; ++i)
        {
            if (strcmp(lastname, entries[i].lastName) == 0)
            {
                cout << "Person Found. " << endl;
                DisplayPerson(i);
                cout << endl;
            }
        }
    };




};


int main() {
    char command;
    bool Exit = false;

    while (Exit == false)
    {
        AddressBook Address_Book;
        cout << "---------------COMMANDS---------------" << endl;
        cout << "A: Add Person To Address Book" << endl;
        cout << "S: Search for Person in Address Book" << endl;
        cout << "D: Display Everyone In Address Book" << endl << endl;

        cout << "Type the letter of your command: ";
        cin >> command;
        cout << endl;
        switch (command) {
        case 'A':
        case 'a':
            Address_Book.AddPerson();
            break;
        case 'S':
        case 's':
            Address_Book.SearchPerson();
            break;
        case 'D':
        case 'd':
            Address_Book.DisplayEveryone();
            break;
        default:
            cout << "That is not a valid command. Closing Address Book." << endl;

            cout << endl;
        }
    }
}

Answer 1

原因是您在while循环的每次迭代中创建一个新的地址簿，并在迭代结束时将其丢弃：

这个

AddressBook Address_Book;

创建一个新的地址簿，然后扔掉＃34;当你到达其范围的末尾时（即循环结束）。

实际上，无论何时想要新的地址，你都会购买新的地址簿吗？不。你首先购买这本书，然后（可能在一个循环中）你添加条目。将上面一行移到循环之外。

Answer 2

您的问题出在您的地址簿声明中。

将其更改为以下内容：

AddressBook Address_Book;

while (Exit == false) {
    //Ask for input and respond.
}

在您的版本中Address_Book在while循环开始时声明。这意味着每次循环的迭代完成并且执行返回到块的开头时，就会创建一个不知道先前对象数据的新本地Address_Book对象。

程序不保存输入的条目？（C ++）

2 个答案:

程序不保存输入的条目？ （C ++）

2 个答案:

程序不保存输入的条目？（C ++）