Question

我努力了但是我无法让它发挥作用。我的方法＆＃34;猜测＆＃34;在课堂上＃34;游戏＆＃34;应该比较参数＆＃34; someInt＆＃34;用变量＆＃34; x＆＃34;来自班级＆＃34; Number＆＃34;。我真的很感激任何帮助，我必须在今晚完成这项工作。到目前为止，这就是我所得到的：

public class Number
{
private int x;

/**
 * Constructor for class Number.
 * This constructor assigns x to a new random 
 * number between 1 and 100
 */
public Number()
{
    // The following lines creates a random number 
    // between 1 and 100 and assigns it to x
    java.util.Random random = new java.util.Random();
    x = random.nextInt(100) + 1;
}

public int getNumber(){
    return x;
}
}

我的另一堂课：

public class Game
{
private Number number;

/**
 * This constructor should initialize the filed number
 */
public Game() {
   Number number1 = new Number();
   number1.getNumber(x);

}

/**
 * This method takes a parameter "someInt" and 
 * compares it with the value stored in "this.number".
 * If "someInt" is less than the value stored in "this.number",
 * then the system should print "Your guess is too small" on the screen;
 * if "someInt" is larger than that value,
 * then the system should print "Your guess is too large" on the screen;
 * otherwise it should print "You win!".
 */
public void guess(int someInt) {
    if (someInt < x){
        System.out.println("Your guess is too small");
    }
    else if (someInt > x) {
        System.out.println("Your guess is too large");
    }
    else {
        System.out.println("You win!");
    }    
}
}

Answer 1

这是修改后的版本

public class Game
{
private Number number;

/**
 * This constructor should initialize the filled number
 */
public Game() {
   this.number = new Number();

}

/**
 * This method takes a parameter "someInt" and 
 * compares it with the value stored in "this.number".
 * If "someInt" is less than the value stored in "this.number",
 * then the system should print "Your guess is too small" on the screen;
 * if "someInt" is larger than that value,
 * then the system should print "Your guess is too large" on the screen;
 * otherwise it should print "You win!".
 */
public void guess(int someInt) {
    if (someInt < number.getNumber()){
        System.out.println("Your guess is too small");
    }
    else if (someInt > number.getNumber()) {
        System.out.println("Your guess is too large");
    }
    else {
        System.out.println("You win!");
    }    
}
}

另一方面，您不应使用与java.lang中名称相同的类作为Number。这会分散注意力，使您的代码难以阅读并且具有错误性。

问题是：

Number.getNumber()没有参数，你提供了一个
您在number1。

number

在guess()中，您使用的是x，而应使用Number.getNumber()。

我建议将Number重命名为不会导致java.lang.Number名称冲突的内容。

Answer 2

这是错误的：

public Game() {
   Number number1 = new Number();
   number1.getNumber(x);

}

因为Number.getNumber()没有参数，必须返回一个int（它是 GETTER ）...

也许你打算这样做：

public class Game {
    private int x;
    private Number number;

/**
 * This constructor should initialize the filed number
 */
public Game() {
   Number number1 = new Number();
   this.x = number1.getNumber();

}

Answer 3

你有number1.getNumber（x）; ，但你的数字类中的getNumber没有参数。

在getNumber方法中，您返回x。你需要在游戏中处理它：

int numberToCompare; （在私人号码下面声明）

number1.getNumber（X）;必须是numberToCompare = number1.getNumber（）;

然后你需要将someint与numberToCompare进行比较。

与其他类的变量比较

3 个答案: