Question

我有这个C ++代码，并且在json序列化时遇到了麻烦。

 string uInput;
 string const& retInput;
 while(!std::cin.eof()) {
   getline(cin, uInput);
   JSONExample source; //JSON enabled class from jsonserialize.h
   source.text = uInput;
   //create JSON from producer
   std::string json = JSON::producer<JSONExample>::convert(source); //string -> returns {"JSONExample":{"text":"hi"}}
   //then create new instance from a consumer...
   JSONExample sink = JSON::consumer<JSONExample>::convert(json);
   //retInput = serialize(sink);
   // Json::FastWriter fastWriter;
   // retInput = fastWriter.write(uInput);
   retInput = static_cast<string const&>(uInput);
   pubnub::futres fr_2 = pb_2.publish(chan, retInput);
   cout << "user input as json which should be published is " << retInput<< std::endl;

Answer 1

 while(!cin.eof()) {
   getline(cin, uInput);
   newInput = "\"\\\""; 
   newInput += uInput;
   newInput += "\\\"\"";

此代码不是输入“\”hi \“”这样的消息，而是采用“hi”并执行此操作。

Answer 2

如果您所描述的更改成为＆＃34;无效的JSON＆＃34;消失，然后更正确＆＃34;解决方案是AFAICT，将publish()行更改为：

pubnub::futres fr_2 = pb_2.publish(chan, json);

因为json已经有JSON序列化数据。当然，如果你想要发布那个JSON。

json序列化c ++

2 个答案: