Question

我正试图通过使用此

来超载Age

Date DOB
getAge()
getAge(Date DOB)

把我不知道如何超载这种方法可以有人帮我吗？

public class Customer
{
    private string CustomerID;
    private string FirstName;
    private string LastName;
    private int Age;
    private string Address;
    private double phoneNumber;

    public Customer(string CustomerID, string FirstName, string LastName, int Age, string Address, double phoneNumber)
    {
        this.CustomerID = CustomerID;
        this.FirstName = FirstName;
        this.LastName = LastName;
        this.Age = Age;
        this.Address = Address;
        this.phoneNumber = phoneNumber;
    }

    public int age {get ; set; }
}
}

Answer 1

要重载，请指定具有相同类型和名称但具有不同参数的方法。例如：

public int Foo(int bar)
{
  return bar*2
}

public int Foo(string bar)
{
  return bar.Length*2;
}

然后，当您引用Foo方法时，您将获得1次重载，字符串参数为1。

然而，

你的类型的年龄部分不是方法，它是一个字段。字段不同，因为在实例化类型（var foo = new Person()）时可以访问和编辑（取决于getter和setter）。

Answer 2

我不确定你要问的是什么，但也许这可能会有所帮助，下面的示例显示了客户类构造函数的另一个重载，以及一个GetAge方法传递出生日期和返回年龄。

    public class Customer
{
    private string CustomerID;
    private string FirstName;
    private string LastName;
    private int Age;
    private string Address;
    private double phoneNumber;

    public Customer(string customerId, string firstName, string lastName, int age, string address, double phoneNumber)
    {
        this.CustomerID = customerId;
        this.FirstName = firstName;
        this.LastName = lastName;
        this.Age = age;
        this.Address = address;
        this.phoneNumber = phoneNumber;
    }

    // overloading the Customer constructor passing in the 'Date of Birth' instead of the age
    public Customer(string customerId, string firstName, string lastName, DateTime dateOfBirth, string address, double phoneNumber)
        : this(customerId, firstName, lastName, GetAge(dateOfBirth), address, phoneNumber) // uses the previous constructor
    { }

    public int age { get; set; }

    // Calculating the age
    private static int GetAge(DateTime dob)
    {
        var age = 0;
        var today = DateTime.Today;

        age = today.Year - dob.Year;
        if (dob.AddYears(age) > today)// still has to celebrate birthday this year
            age--;

        return age;
    }
}

我怎样才能在c＃中重载方法？

2 个答案: