Question

有什么问题？

我的子查询返回NULL。

我想做什么？

我正在使用如下表格：

------------------------------------------------------------------
|        url          |  page_path_1  |  page_path_2  |  filter  |
------------------------------------------------------------------
|  e.com/test1/test2/  |     test1     |     test2    |   foo    |
|  e.com/test1/test2/  |     test1     |     test2    |   bar    |
|  e.com/test2/test3/  |     test2     |     test3    |   foo    |

我想为按降序foo排序的前20个目录组合中的每一个返回20个示例网址。

我目前的查询是什么？

SELECT
  url
FROM 
  [table.data_analysis],
  (
      SELECT
        page_path_1 as pp1, page_path_2 as pp2, count(page_path_1) as count, filter
      FROM
        [table.data_analysis]
      WHERE
       filter = foo
      GROUP BY pp1, pp2, filter
      ORDER BY count desc
      LIMIT 20
    ) AS sub_query
WHERE
  filter = foo and
  page_path_1 = pp1 and
  page_path_2 = pp2
LIMIT 20

如果你自己运行它，

sub_query会返回有效的目录：

Row  |   pp1   |  pp2    |   count  |  filter  |
-----------------------------------------------
1    |  test1  |  test2  |    1     |   foo
1    |  test2  |  test3  |    1     |   foo

但是当你将它用作实际的子查询时，请看一下pp1＆amp; PP2：

SELECT
  pp1, pp2
FROM 
  [table.data_analysis],
  (
      SELECT
        page_path_1 as pp1, page_path_2 as pp2, count(page_path_1) as count, filter
      FROM
        [table.data_analysis]
      WHERE
       filter = foo
      GROUP BY pp1, pp2, filter
      ORDER BY count desc
      LIMIT 20
    ) AS sub_query
WHERE
  filter = foo
LIMIT 20

它返回null。

Row  |  pp1  |   pp2     
----------------------
1    |  null |   null
2    |  null |   null
3    |  null |   null

我完全难过了。我怎么错误地使用这个？

Answer 1

我怎么错误地使用它？

希望下面的简化示例可以让您了解这里的错误

SELECT filter, pp1, pp2
FROM (
  SELECT a, b, filter
  FROM 
    (SELECT 1 AS a, 21 AS b, 'foo' AS filter),
    (SELECT 2 AS a, 22 AS b, 'foo' AS filter),
    (SELECT 3 AS a, 23 AS b, 'foo1' AS filter),
    (SELECT 4 AS a, 24 AS b, 'foo1' AS filter),
    (SELECT 5 AS a, 25 AS b, 'foo' AS filter)
  ), (
  SELECT pp1, pp2, filter
  FROM 
    (SELECT 1 AS pp1, 21 AS pp2, 'foo' AS filter),
    (SELECT 2 AS pp1, 22 AS pp2, 'foo1' AS filter),
    (SELECT 3 AS pp1, 23 AS pp2, 'foo' AS filter),
    (SELECT 4 AS pp1, 24 AS pp2, 'foo' AS filter),
  )
WHERE filter = 'foo'
LIMIT 2

结果是

filter  pp1 pp2  
foo null    null     
foo null    null

在这里，您使用的是UNION ALL BigQuery Legacy SQL的逗号样式 UNION中的第一篇文章没有pp1和pp2，这就是为什么它们带有NULL

BigQuery为子查询返回null

1 个答案: