Question

我是oracle sqldevelop的新手。我在这样的更新表中遇到了麻烦。

table1
+----+-----------+------------+
| id |  acoount  |    date    |
+----+-----------+------------+
|    |  John     |  2/6/2016  | 
|    |  John     |  2/6/2016  |

我有一个名为table1的表。我想更新id只更新一行的地方。示例：

+----+-----------+------------+
| id |  acoount  |    date    |
+----+-----------+------------+
|  1 |  John     |  2/6/2016  | 
|  2 |  John     |  2/6/2016  |

解决方案如何。感谢

Answer 1

Oracle安装程序：

CREATE TABLE table1 ( id,  account, "date" ) AS
SELECT CAST( NULL AS INT ), 'John', DATE '2016-06-02' FROM DUAL UNION ALL
SELECT CAST( NULL AS INT ), 'John', DATE '2016-06-02' FROM DUAL;

<强>更新：

MERGE INTO TABLE1 d
USING ( SELECT ROWNUM AS id, ROWID AS rid FROM Table1 ) s
      ON ( d.ROWID = s.RID )
WHEN MATCHED THEN
  UPDATE SET d.id = s.id;

<强>结果：

SELECT * FROM table1;

        ID ACCOUNT date              
---------- ------- -------------------
         1 John    2016-06-02 00:00:00 
         2 John    2016-06-02 00:00:00

仅在oracle sqldevelop中更新一行

1 个答案: