Question

  using UnityEngine;
  public class Player : MonoBehaviour
    {
        // The force which is added when the player jumps
        // This can be changed in the Inspector window
        public Vector2 jumpForce = new Vector2(0, 300);
        // Update is called once per frame
            void Update ()
            {
                // Jump`enter code here
                if (Input.GetKeyUp("space")) /*This is written for spacebar event so how can make it a touch event and to use in it android project */
                {
                    GetComponent<Rigidbody2D>().velocity = Vector2.zero; GetComponent<Rigidbody2D>().AddForce(jumpForce);//It all works fine
                }
            }
        }

Answer 1

如果您正在寻找屏幕上任何地方的简单按，那就应该这样做。

 C:\opts\Python27>pip install requests
 Collecting requests
 Could not find a version that satisfies the requirement requests (from versions: )
 No matching distribution found for requests

OR

if (Input.GetMouseButtonDown(0))
{
   GetComponent<Rigidbody2D>().velocity = Vector2.zero; 
   GetComponent<Rigidbody2D>().AddForce(jumpForce);
}

如果您正在寻找屏幕上的Button UI，learn Unity UI系统。

如何将统一中的空格键事件转换为android中的触摸事件？

1 个答案: