Question

这个游戏代码看起来不错，但它不起作用：

//Get canvas and context
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');

//Capture keypresses
var keys = [];
document.onKeyDown = function (e) {keys[e.keyCode] = true;};
document.onKeyUp = function (e) {keys[e.keyCode] = false;};

//Set game variables
var characters;
characters.charList = [];
var player = {};

//Character constructor
function Character (Name, Strength, Speed, Intelligence, Reflexes, Age, Height, Weight, Weapon, UsesMagic, MagicType, Armor, Hair, Eyes, Skin, Clothes, Species, Type, Accessories) {
        this.name = Name;
        this.strength = Strength;
    this.speed = Speed;
    this.intelligence = Intelligence;
    this.reflexes = Reflexes;
    this.age = Age;
    this.height = Height;
    this.weight = Weight;
    this.weapon = Weapon;
    this.usesMagic = UsesMagic;
    this.magicType = MagicType;
    this.armor = Armor;
    this.hair = Hair;
    this.eyes = Eyes;
    this.skin = Skin;
    this.clothes = Clothes;
    this.species = Species;
    this.type = Type;
    if (Accessories) {
            this.accessories = Accessories;
    }
    characters.charList[characters.charList.length] = Name;
}

characters.Xantar = new Character('Xantar', 1, 1, 1, 1, 1, 1, 1, 'sword', true, 'derp', [], 'hair is brown\?', 'duh', 'foo', [], 'animale', 'wolf', []);
alert(characters.Xantar.weapon + '   ' + characters[0].type);

//Activate mainloop and get value for pausing purposes
var mainloopInterval = setInterval(mainloop, 5);
//Main game loop
function mainloop(){

}

该计划似乎停在：

characters.charList = [];

我根本就没有在这里看到问题。这是相关的HTML：

<canvas id='canvas' style='border:1px solid black;'>Your browser does not support canvas. Please update your browser.</canvas>

注意：我在JSFiddle上运行它。如果有人能在这里帮助我，我将非常感激。以下是链接：https://jsfiddle.net/q6vdph1p/14/。

Answer 1

需要将其设置为对象var characters = {};

Answer 2

变量＆＃34;字符＆＃34;必须是一个对象。 var characters = {};
charList不应该用＆＃34; var＆＃34;初始化。关键字，因为它不是新变量，因此它只是characters.charList = [];
在第42行，它不是characters[0].type，而是characters.Xantar.type JSFiddle

Answer 3

如前所述，您需要先为characters变量指定一个对象，然后才能访问其中的属性。

只需使用var characters;声明它就会为其分配undefined的值并尝试访问undefined.charList并为其分配一个空数组将失败。

更正确，失败和可读的方式来声明它将构建空数据结构，如下所示：

var characters = {
    charList: []
};

此外，使用array.push()添加到数组末尾比使用array.length索引更安全，即

characters.charList.push(Name);

而不是

characters.charList[characters.charList.length] = Name;

设置变量时游戏代码中断

3 个答案: