Question

我是代码新手，请原谅我这个问题的答案是否明显！

我正在从API收集JSON数据，我有一个值ExpectedDateTime，我想用它来计算 now 的分钟数和秒数。

格式为：2016-05-09T12：26：26

我试过这个：

 function applyTimeToVallingby(data) {
        $scope.timeToVallingby = 0;
        $scope.timeToVallingby2 = 0;
        d = new Date();
        for(i=0;i<data.ResponseData.Buses.length;i++){
            if(data.ResponseData.Buses[i].JourneyDirection === 2){
                if($scope.timeToVallingby===0){
                    $scope.timeToVallingby=(d-data.ResponseData.Buses[i].ExpectedDateTime);
                }else if($scope.timeToVallingby!=0&&$scope.timeToVallingby2===0){
                    $scope.timeToVallingby2=d-data.ResponseData.Buses[i].ExpectedDateTime;
                }
            }
        }
    }

但它不起作用。我试图找到一种方法将新的Date（）值转换为类似于ExpectedDateTime的格式，这样我就可以减去，但是还没有能够。

致以最诚挚的问候，

Answer 1

时间的差异：

var date = new Date('2016-05-09T12:26:26');
var now = new Date();
alert(" Seconds from now : " + parseInt( (now.getTime() - date.getTime())/1000 ) );

以你的方式 - d.getTime() - new Date( data.ResponseData.Buses[i].ExpectedDateTime).getTime()

Answer 2

也许您可以使用Moment.js库：

$scope.daysLeft = function (end_date) {
        var now = moment();
        var then = moment(end_date);
        var diff = then.diff(now, 'days');

        if(diff <= 0)
            return 0;

        return diff;
}

Answer 3

您需要先将ExpectedDateTime转换为日期对象

var expectedDateTime = "2016-05-09T12:26:26";

var items = expectedDateTime.split("T");
var dates = items[0].split("-");
var times = items[1].split(":");

var expectedDateObj = new Date( dates[0], dates[1]-1, dates[2], times[0], times[1], times[2] );

现在简单地获取与now和此expectedDateObj对象

的毫秒差异数

var now = new Date();
var noOfMS = now.getTime() - expectedDateObj.getTime();
var numberOfSeconds = noOfMS/1000;

var noOfMinAndSec = "Min = " + numberOfSeconds/60 + " Sec = " + numberOfSeconds%60;

<强>样本

＆＃13;

var expectedDateTime = "2016-05-09T12:26:26";

var items = expectedDateTime.split("T");
var dates = items[0].split("-");
var times = items[1].split(":");

var expectedDateObj = new Date( dates[0], dates[1]-1, dates[2], times[0], times[1], times[2] );



var now = new Date();
var noOfMS = now.getTime() - expectedDateObj.getTime();
var numberOfSeconds = Math.floor(Math.abs(noOfMS/1000));

var noOfMinAndSec = "Min = " + parseInt(numberOfSeconds/60) + " Sec = " + numberOfSeconds%60;

alert( noOfMinAndSec );

＆＃13;

如何从javascript开始计算时间？

3 个答案: