我需要编写一个过程来规范化一个记录,该记录具有由一个char连接的多个标记。我需要获取这些标记分割字符串并将每个标记作为新记录插入表中。 Oracle是否具有类似“拆分”功能的东西?
答案 0 :(得分:34)
有apex_util.string_to_table
- 请my answer查看此question。
此外,在存在上述功能之前,我曾发布过解决方案here on my blog。
在APEX的更高版本中,apex_util.string_to_table
为deprecated,并且首选类似的函数apex_string.split。
答案 1 :(得分:15)
你必须自己动手。如,
/* from :http://www.builderau.com.au/architect/database/soa/Create-functions-to-join-and-split-strings-in-Oracle/0,339024547,339129882,00.htm
select split('foo,bar,zoo') from dual;
select * from table(split('foo,bar,zoo'));
pipelined function is SQL only (no PL/SQL !)
*/
create or replace type split_tbl as table of varchar2(32767);
/
show errors
create or replace function split
(
p_list varchar2,
p_del varchar2 := ','
) return split_tbl pipelined
is
l_idx pls_integer;
l_list varchar2(32767) := p_list;
l_value varchar2(32767);
begin
loop
l_idx := instr(l_list,p_del);
if l_idx > 0 then
pipe row(substr(l_list,1,l_idx-1));
l_list := substr(l_list,l_idx+length(p_del));
else
pipe row(l_list);
exit;
end if;
end loop;
return;
end split;
/
show errors;
/* An own implementation. */
create or replace function split2(
list in varchar2,
delimiter in varchar2 default ','
) return split_tbl as
splitted split_tbl := split_tbl();
i pls_integer := 0;
list_ varchar2(32767) := list;
begin
loop
i := instr(list_, delimiter);
if i > 0 then
splitted.extend(1);
splitted(splitted.last) := substr(list_, 1, i - 1);
list_ := substr(list_, i + length(delimiter));
else
splitted.extend(1);
splitted(splitted.last) := list_;
return splitted;
end if;
end loop;
end;
/
show errors
declare
got split_tbl;
procedure print(tbl in split_tbl) as
begin
for i in tbl.first .. tbl.last loop
dbms_output.put_line(i || ' = ' || tbl(i));
end loop;
end;
begin
got := split2('foo,bar,zoo');
print(got);
print(split2('1 2 3 4 5', ' '));
end;
/
答案 2 :(得分:13)
如果APEX_UTIL
不可用,您可以使用REGEXP_SUBSTR()
解决方案。
灵感来自http://nuijten.blogspot.fr/2009/07/splitting-comma-delimited-string-regexp.html:
DECLARE
I INTEGER;
TYPE T_ARRAY_OF_VARCHAR IS TABLE OF VARCHAR2(2000) INDEX BY BINARY_INTEGER;
MY_ARRAY T_ARRAY_OF_VARCHAR;
MY_STRING VARCHAR2(2000) := '123,456,abc,def';
BEGIN
FOR CURRENT_ROW IN (
with test as
(select MY_STRING from dual)
select regexp_substr(MY_STRING, '[^,]+', 1, rownum) SPLIT
from test
connect by level <= length (regexp_replace(MY_STRING, '[^,]+')) + 1)
LOOP
DBMS_OUTPUT.PUT_LINE(CURRENT_ROW.SPLIT);
MY_ARRAY(MY_ARRAY.COUNT) := CURRENT_ROW.SPLIT;
END LOOP;
END;
/
答案 3 :(得分:9)
这仅适用于Oracle 10G及更高版本。
基本上,您使用regex_substr对字符串进行拆分。
答案 4 :(得分:5)
您可以使用SUBSTR和INSTR的组合,如下所示:
示例字符串:field = 'DE124028#@$1048708#@$000#@$536967136#@$'
分隔符是#@ $。
以获得'1048708'为例:
如果字段长度固定(此处为7):
substr(field,instr(field,'#@$',1,1)+3,7)
如果字段长度可变:
substr(field,instr(field,'#@$',1,1)+3,instr(field,'#@$',1,2) - (instr(field,'#@$',1,1)+3))
您应该查看SUBSTR和INSTR函数以获得更大的灵活性。
答案 5 :(得分:5)
请参阅下一个您可能会觉得有用的示例
- 第一个子串
select substr('alfa#bravo#charlie#delta', 1,
instr('alfa#bravo#charlie#delta', '#', 1, 1)-1) from dual;
- 第二个子串
select substr('alfa#bravo#charlie#delta', instr('alfa#bravo#charlie#delta', '#', 1, 1)+1,
instr('alfa#bravo#charlie#delta', '#', 1, 2) - instr('alfa#bravo#charlie#delta', '#', 1, 1) -1) from dual;
- 第3个子串
select substr('alfa#bravo#charlie#delta', instr('alfa#bravo#charlie#delta', '#', 1, 2)+1,
instr('alfa#bravo#charlie#delta', '#', 1, 3) - instr('alfa#bravo#charlie#delta', '#', 1, 2) -1) from dual;
- 第4个子串
select substr('alfa#bravo#charlie#delta', instr('alfa#bravo#charlie#delta', '#', 1, 3)+1) from dual;
祝你好运
Emanuele的
答案 6 :(得分:4)
您可以使用regexp_substr()。例如:
create or replace type splitTable_Type is table of varchar2(100);
declare
l_split_table splitTable_Type;
begin
select
regexp_substr('SMITH,ALLEN,WARD,JONES','[^,]+', 1, level)
bulk collect into
l_split_table
from dual
connect by
regexp_substr('SMITH,ALLEN,WARD,JONES', '[^,]+', 1, level) is not null;
end;
查询迭代逗号分隔的字符串,搜索逗号(,)然后通过将逗号视为分隔符来拆分字符串。只要它到达分隔符,它就会将字符串作为一行返回。
语句level
中的 regexp_substr('SMITH,ALLEN,WARD,JONES','[^,]+', 1, level)
指的是Oracle中的伪列,它在分层查询中用于以数字格式标识层次结构级别:level in connect by
答案 7 :(得分:1)
function numinstr(p_source in varchar2,p_token in varchar2)
return pls_integer
is
v_occurrence pls_integer := 1;
v_start pls_integer := 1;
v_loc pls_integer;
begin
v_loc:=instr(p_source, p_token, 1, 1);
while v_loc > 0 loop
v_occurrence := v_occurrence+1;
v_start:=v_loc+1;
v_loc:=instr(p_source, p_token, v_start, 1);
end loop;
return v_occurrence-1;
end numinstr;
--
--
--
--
function get_split_field(p_source in varchar2,p_delim in varchar2,nth pls_integer)
return varchar2
is
v_num_delims pls_integer;
first_pos pls_integer;
final_pos pls_integer;
len_delim pls_integer := length(p_delim);
ret_len pls_integer;
begin
v_num_delims := numinstr(p_source,p_delim);
if nth < 1 or nth > v_num_delims+1 then
return null;
else
if nth = 1 then
first_pos := 1;
else
first_pos := instr(p_source, p_delim, 1, nth-1) + len_delim;
end if;
if nth > v_num_delims then
final_pos := length(p_source);
else
final_pos := instr(p_source, p_delim, 1, nth) - 1;
end if;
ret_len := (final_pos - first_pos) + 1;
return substr(p_source, first_pos, ret_len);
end if;
end get_split_field;
答案 8 :(得分:0)
我需要一个用于拆分Clob的函数,并确保该函数在sql中可用。
create or replace type vchar_tab is table of varchar2(4000)
/
create or replace function split(
p_list in clob,
p_separator in varchar2 default '|'
) return vchar_tab pipelined is
C_SQL_VCHAR_MAX constant integer:=4000;
C_MAX_AMOUNT constant integer:=28000;
C_SEPARATOR_LEN constant integer:=length(p_separator);
l_amount integer:=C_MAX_AMOUNT;
l_offset integer:=1;
l_buffer varchar2(C_MAX_AMOUNT);
l_list varchar2(32767);
l_index integer;
begin
if p_list is not null then
loop
l_index:=instr(l_list, p_separator);
if l_index > C_SQL_VCHAR_MAX+1 then
raise_application_error(-20000, 'item is too large for sql varchar2: len='||(l_index-1));
elsif l_index > 0 then -- found an item, pipe it
pipe row (substr(l_list, 1, l_index-1));
l_list:=substr(l_list, l_index+C_SEPARATOR_LEN);
elsif length(l_list) > C_SQL_VCHAR_MAX then
raise_application_error(-20001, 'item is too large for sql varchar2: length exceeds '||length(l_list));
elsif l_amount = C_MAX_AMOUNT then -- more to read from the clob
dbms_lob.read(p_list, l_amount, l_offset, l_buffer);
l_list:=l_list||l_buffer;
else -- read through the whole clob
if length(l_list) > 0 then
pipe row (l_list);
end if;
exit;
end if;
end loop;
end if;
return;
exception
when no_data_needed then -- this happens when you don't fetch all records
null;
end;
/
测试:
select *
from table(split('ASDF|IUYT|KJHG|ASYD'));
答案 9 :(得分:-1)
我喜欢那个顶级实用程序的外观。但是,了解可用于此的标准oracle函数也很好:subStr和inStr http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions001.htm
答案 10 :(得分:-1)
人们有一种简单的方法。使用REPLACE功能。下面是一个逗号分隔的字符串示例,可以传递给IN子句。
在PL / SQL中:
StatusString := REPLACE('Active,Completed', ',', ''',''');
在SQL Plus中:
Select REPLACE('Active,Completed', ',', ''',''') from dual;