def mapping(list_of_files , list_of_folders, max1):
print max1
max1 += 1
if len(list_of_folders) == 0:
folder = os.walk(os.getcwd()).next()[1]
files = os.listdir(os.getcwd())
elif len(list_of_files) != 0:
print list_of_folders[0]
## for some reason this of line of code stops working without error on 20150 iteration
folder = next(os.walk(os.getcwd() +'/' + list_of_folders[0]))[1]
#folder = os.walk(os.getcwd() +'/' + list_of_folders[0] ).next()[1]
#print os.listdir(os.getcwd() + '/' +list_of_folders[0])
files = os.listdir(os.getcwd() + '/' +list_of_folders[0])
length = len(folder)
length1 = len (files)
y = 0
if folder == files:
del files[:]
else :
for x in range(length):
while y != length1:
if files[y] == folder[x]:
files.pop(y)
length1 = length1 - 1
y = 0
y += 1
y = 0
#print folder
#print files
if len(list_of_folders) == 0:
list_of_files = add_to_main_lists(list_of_files,'', files)
#print list_of_files
list_of_folders = add_to_main_lists(list_of_folders, '', folder)
#print list_of_folders
else:
list_of_files = add_to_main_lists(list_of_files,list_of_folders[0], files)
#print list_of_files
list_of_folders = add_to_main_lists(list_of_folders, list_of_folders[0], folder)
#print list_of_folders
list_of_folders.pop(0)
if len(list_of_folders) == 0:
print "got to here"
return list_of_files
else:
print "file length: " + str(len(list_of_files))
print "folder length: " + str(len(list_of_folders))
mapping(list_of_files , list_of_folders, max1)
return list_of_files
list_of_files = []
list_of_folders = []
list_of_files = mapping(list_of_files, list_of_folders , max1)
print (list_of_files)
该文件应该映射文件所在的文件夹及其所有子目录。出于某种原因,当代码运行其20150迭代时,该行 folder = next(os.walk(os.getcwd()+'/'+ list_of_folders [0]))[1] 终止代码并且不会抛出任何错误。我不知所措。我使用sudo运行代码。
答案 0 :(得分:2)
我可以在代码中看到两件事:
您在同一次迭代中对生成器调用.next()
两次。我不认为这是你想要做的,你的迭代将解析两个不同的os.walk
输出。将os.walk(os.getcwd()).next()
的输出保存在var中并使用它。
只有当前级别中没有文件夹时,您才会处理文件列表,因为您正在使用elif
来执行list_of_files
。您应该使用if
,因为无论如何都要处理它。
此外,请记住,迭代器的结尾会引发StopIteration
异常,因此这很可能发生了什么。你需要处理那个例外。