Question

嘿大家我收到错误＆＃34;未定义的索引：fileToUpload＆＃34;两次，我似乎无法弄清楚为什么。错误发生在// ERROR标记所在的位置。包含Html表单。任何帮助将不胜感激。

<?php
$target_dir = "images/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]); //ERROR 1
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}
 // Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) { //ERROR 2
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
 }
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}

?>  
<h1>Upload</h1>
<form action="Upload.php" method="post" enctype="multipart/form-data">
    Select image to upload:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
 </form>

Answer 1

您需要检查表单是否已提交，然后在其中执行所有文件上载检查代码类似......

scrapy crawl article_spider -a id=1 -a do_action=yes

希望它有所帮助！

Answer 2

首先，您可以使用javascript

检查用户是否在客户端选择了一个文件

$('form').on('submit',function(event){
    if( document.getElementById("fileToUpload").files.length == 0 ){
        alert("You must select a file");
        event.preventDefault();
    }
})

然后你也可以检查用户实际提交文件的服务器sidde php代码

if(!isset($_FILES["fileToUpload"]["name"])|| $_FILES["fileToUpload"]["size"] <1) exit();

Answer 3

这实际上是因为$_FILES["fileToUpload"]变量/数组尚未设置。你需要先进一步设置它。您可以使用简单的if语句尝试它。

if(isset($_FILES["fileToUpload"]))
{
 //your code
}

上传和图像

3 个答案: