Question

我正在处理Gradle脚本，我需要阅读local.properties文件并使用build.gradle中属性文件中的值。我是以下面的方式做的。我运行下面的脚本，它现在抛出一个错误，但它也没有做任何事情，如创建，删除和复制文件。我试图打印变量的值，它显示正确的值。

如果这是正确的方法，有人可以告诉我吗？我认为另一种方法是在gradle.properties中定义所有内容并在build.gradle中使用它。有人可以告诉我如何从build.gradle访问build.properties中的媒体资源？

build.gradle档案：

apply plugin: 'java'

//-- set the group for publishing
group = 'com.true.test'

/**
 * Initializing GAVC settings
 */
def buildProperties = new Properties()
file("version.properties").withInputStream {
        stream -> buildProperties.load(stream)
}
//if jenkins build, add the jenkins build version to the version. Else add snapshot version to the version.
def env = System.getenv()
if (env["BUILD_NUMBER"]) buildProperties.test+= ".${env["BUILD_NUMBER"]}"
version = buildProperties.test
println "${version}"

//name is set in the settings.gradle file
group = "com.true.test"
version = buildProperties.test
println "Building ${project.group}:${project.name}:${project.version}"

Properties properties = new Properties()
properties.load(project.file('build.properties').newDataInputStream())
def folderDir = properties.getProperty('build.dir')
def configDir = properties.getProperty('config.dir')
def baseDir  = properties.getProperty('base.dir')
def logDir  = properties.getProperty('log.dir')
def deployDir  = properties.getProperty('deploy.dir')
def testsDir  = properties.getProperty('tests.dir')
def packageDir  = properties.getProperty('package.dir')
def wrapperDir  = properties.getProperty('wrapper.dir')


sourceCompatibility = 1.7
compileJava.options.encoding = 'UTF-8'

repositories {
     maven { url "http://arti.oven.c:9000/release" }
  }

task swipe(type: Delete) {
         println "Delete $projectDir/${folderDir}"
         delete "$projectDir/$folderDir"
         delete "$projectDir/$logDir"
         delete "$projectDir/$deployDir"
         delete "$projectDir/$packageDir"
         delete "$projectDir/$testsDir"
         mkdir("$projectDir/${folderDir}")
         mkdir("projectDir/${logDir}")
         mkdir("projectDir/${deployDir}")
         mkdir("projectDir/${packageDir}")
         mkdir("projectDir/${testsDir}")
}
task prepConfigs(type: Copy, overwrite:true, dependsOn: swipe) {
    println "The name of ${projectDir}/${folderDir} and ${projectDir}/${configDir}"
    from('${projectDir}/${folderDir}')
    into('${projectDir}/$configDir}')
    include('*.xml')
}

build.properties档案：

# -----------------------------------------------------------------
# General Settings
# -----------------------------------------------------------------
application.name  = Admin
project.name = Hello Cool

# -----------------------------------------------------------------
# ant build directories
# -----------------------------------------------------------------
sandbox.dir = ${projectDir}/../..
reno.root.dir=${sandbox.dir}/Reno
ant.dir = ${projectDir}/ant
build.dir = ${ant.dir}/build
log.dir  = ${ant.dir}/logs
config.dir = ${ant.dir}/configs
deploy.dir  = ${ant.dir}/deploy
static.dir =  ${ant.dir}/static
package.dir = ${ant.dir}/package
tests.dir = ${ant.dir}/tests
tests.logs.dir = ${tests.dir}/logs
external.dir = ${sandbox.dir}/FlexCommon/External
external.lib.dir = ${external.dir}/libs

Answer 1

如果使用默认的gradle.properties文件，您可以直接从build.gradle文件中访问这些属性：

gradle.properties：

applicationName=Admin
projectName=Hello Cool

build.gradle：

task printProps {
    doFirst {
        println applicationName
        println projectName
    }
}

如果您需要访问自定义文件，或访问其中包含.的属性（您似乎需要这样做），则可以在build.gradle文件中执行以下操作：

def props = new Properties()
file("build.properties").withInputStream { props.load(it) }

task printProps {
    doFirst {
        println props.getProperty("application.name")
        println props.getProperty("project.name")
    }
}

请查看this section of the Gradle documentation了解详情。

修改

如果您想动态设置其中一些属性（如下面的评论中所述），您可以创建一个properties.gradle文件（名称并不重要）并要求它在build.gradle脚本中。

properties.gradle：

ext {
    subPath = "some/sub/directory"
    fullPath = "$projectDir/$subPath"
}

build.gradle

apply from: 'properties.gradle'

// prints the full expanded path
println fullPath

Answer 2

我们可以使用一个单独的文件（在我的情况下为config.groovy）来抽象出所有配置。注意我们如何分离出通用配置的逻辑：

`config.groovy`

resources {
    serverName = 'localhost'
    serverPort = '8090'
}

environments {
    dev {
        serverName = 'http://localhost'   
        serverPort = '8080'
    }

    test {
        serverName = 'http://www.testserver.com'
        serverPort = '5211'
        resources {
            serverName = 'resources.testserver.com'
        }
    }

    prod {
        serverName = 'http://www.productionserver.com'
        serverPort = '80'
        resources {
            serverName = 'resources.productionserver.com'
            serverPort = '80'
        }
    }
}

属性文件准备就绪后，我们可以在build.gradle中使用以下内容来加载这些设置：

`build.gradle`

loadProperties()

def loadProperties() {
    def environment = hasProperty('env') ? env : 'dev'
    println "Current Environment: " + environment

    def configFile = file('config.groovy')
    def config = new ConfigSlurper(environment).parse(configFile.toURL())
    project.ext.config = config
}

task printProperties {
    println "serverName:  $config.serverName"
    println "serverPort:  $config.serverPort"
    println "resources.serverName:  $config.resources.serverName"
    println "resources.serverPort:  $config.resources.serverPort"
}

让我们用不同的输入集来运行它们：

gradle -q printProperties

Current Environment: dev
serverName:  http://localhost
serverPort:  8080
resources.serverName:  localhost
resources.serverPort:  8090

gradle -q -Penv=dev printProperties

Current Environment: dev
serverName:  http://localhost
serverPort:  8080
resources.serverName:  localhost
resources.serverPort:  8090

gradle -q -Penv=test printProperties

Current Environment: test
serverName:  http://www.testserver.com
serverPort:  5211
resources.serverName:  resources.testserver.com
resources.serverPort:  8090

gradle -q -Penv=prod printProperties

Current Environment: prod
serverName:  http://www.productionserver.com
serverPort:  80
resources.serverName:  resources.productionserver.com
resources.serverPort:  80

Answer 3

另一种方法...在build.gradle中：

添加：

classpath 'org.flywaydb:flyway-gradle-plugin:3.1'

这：

def props = new Properties()
file("src/main/resources/application.properties").withInputStream { props.load(it) }
apply plugin: 'flyway'
flyway {
    url = props.getProperty("spring.datasource.url")
    user = props.getProperty("spring.datasource.username")
    password = props.getProperty("spring.datasource.password")
    schemas = ['db_example']
}

如何读取属性文件并使用项目Gradle脚本中的值？

3 个答案:

修改

`config.groovy`

`build.gradle`