Question

JSON我正在处理：

[
  {
    "score":2.860397,
    "show": {
      "id": 82,
      "url": "http://www.tvmaze.com/shows/82/game-of-thrones",
      "name": "Game of Thrones",
      "type": "Scripted",
      "language": "English",
      "genres": [
        "Drama", "Adventure", "Fantasy"
      ],
      "status": "Running",
      "runtime": 60,
      "premiered": "2011-04-17",
      "schedule": {
        "time": "21:00",
        "days": [ "Sunday" ]
      },
      "rating": {
        "average": 9.4
      },
      "weight": 100,
      "network": {
        "id": 8,
        "name": "HBO",
        "country": {
          "name": "United States",
          "code": "US",  
          "timezone": "America/New_York"
        }
      },
      "webChannel": null,
      "externals": {
        "tvrage": 24493,
        "thetvdb": 121361,
        "imdb": "tt0944947"
      },
      "image": { 
        "medium": "http://tvmazecdn.com/uploads/images/medium_portrait/53/132622.jpg",
        "original": "http://tvmazecdn.com/uploads/images/original_untouched/53/132622.jpg"
      },           
      "summary": "<p>Based on the bestselling book series A Song of Ice and Fire by George R.R. Martin, this sprawling new HBO drama is set in a world where summers span decades and winters can last a lifetime. From the scheming south and the savage eastern lands, to the frozen north and ancient Wall that protects the realm from the mysterious darkness beyond, the powerful families of the Seven Kingdoms are locked in a battle for the Iron Throne. This is a story of duplicity and treachery, nobility and honor, conquest and triumph. In the <strong><em>\"Game of Thrones\"</em></strong>, you either win or you die.</p>",
      "updated": 1462561599,
      "_links": {
        "self": {
          "href": "http://api.tvmaze.com/shows/82"
        }, 
        "previousepisode": {  
          "href": "http://api.tvmaze.com/episodes/664672"
         },
        "nextepisode": {
          "href": "http://api.tvmaze.com/episodes/664673"
        }
      }
    } 
  }
]

我的代码：

JsonArrayRequest request = new JsonArrayRequest(Request.Method.GET, final_url, (String)null,
    new Response.Listener<JSONArray>() {
        @Override
        public void onResponse(JSONArray response) {
            try {
                JSONArray jArray = new JSONArray(response);

                for(int i=0; i<jArray.length(); i++) {
                    JSONObject json_object = (JSONObject)jArray.get(i);
                    String name = json_object.getString("name");
                    System.out.println(name);
                }
            } catch(JSONException e) {
                System.out.println(e);
            }
        }
    },
    new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            System.out.println(error);
        }
    }
);

我见过有很多这样的问题，但大多数问题都与JSONObject而不是JSONArray有关，我找不到适用于我的解决方案。

我仍然在标题中提到错误。有什么帮助吗？

更新：到目前为止尝试了除gson以外的一切，但仍然无效。堆栈跟踪是：

05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     org.json.JSONException: Not a primitive array: class org.json.JSONArray
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at org.json.JSONArray.<init>(JSONArray.java:116)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at com.example.user.test.SearchActivity$2$override.onResponse(SearchActivity.java:134)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at com.example.user.test.SearchActivity$2$override.access$dispatch(SearchActivity.java)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at com.example.user.test.SearchActivity$2.onResponse(SearchActivity.java:0)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at com.example.user.test.SearchActivity$2.onResponse(SearchActivity.java:115)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at com.android.volley.toolbox.JsonRequest.deliverResponse(JsonRequest.java:72)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at com.android.volley.ExecutorDelivery$ResponseDeliveryRunnable.run(ExecutorDelivery.java:99)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at android.os.Handler.handleCallback(Handler.java:739)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at android.os.Handler.dispatchMessage(Handler.java:95)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at android.os.Looper.loop(Looper.java:135)
05-08 14:18:14.790 2628-2628/com.example.user.test W/System.err:     at android.app.ActivityThread.main(ActivityThread.java:5254)
05-08 14:18:14.797 2628-2628/com.example.user.test W/System.err:     at java.lang.reflect.Method.invoke(Native Method)
05-08 14:18:14.797 2628-2628/com.example.user.test W/System.err:     at java.lang.reflect.Method.invoke(Method.java:372)
05-08 14:18:14.801 2628-2628/com.example.user.test W/System.err:     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:903)
05-08 14:18:14.801 2628-2628/com.example.user.test W/System.err:     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:698)

更新2：我的wole searchActivity.java也许错误在别的地方（我删除了数组以查看它是否会改变除了nope之外）：

公共类SearchActivity扩展了AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_search);



    final EditText editText = (EditText) findViewById(R.id.searchView);
    editText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            boolean handled = false;
            if (actionId == EditorInfo.IME_ACTION_SEARCH) {
                String query = editText.getText().toString();
                //doMySearch(query);
                clearQuery(query);
                handled = true;
            }
            return handled;
        }
    });


}

public void clearQuery(String query) {
    query = query.replaceAll("[^\\w\\s]","").replaceAll("\\s+","-"); //TVMaze API uses "-" as spaces

    doMySearch(query);

}


public void doMySearch(String query) {
    System.out.println("print if doMySearch was opened");
    System.out.println(query);
    List<Show> subscribedShowsList = new ArrayList<Show>();

    String url = "http://api.tvmaze.com/search/shows?q=";
    String final_url = url + query;

    RequestQueue mRequestQueue;

// Instantiate the cache
    Cache cache = new DiskBasedCache(getCacheDir(), 1024 * 1024); // 1MB cap

// Set up the network to use HttpURLConnection as the HTTP client.
    Network network = new BasicNetwork(new HurlStack());

// Instantiate the RequestQueue with the cache and network.
    mRequestQueue = new RequestQueue(cache, network);



    JsonArrayRequest request = new JsonArrayRequest(Request.Method.GET, final_url, (String)null,
            new Response.Listener<JSONArray>() {
                @Override
                public void onResponse(JSONArray response) {

                    System.out.println("print if we got to onResponse");
                    try {
                        JSONArray jArray = new JSONArray(response);

                        JSONObject joParent = response.getJSONObject(0);
                        JSONObject joShow = joParent.getJSONObject("show");
                        String name = joShow.getString("name");
                        System.out.println(name);

                    } catch(JSONException e) {
                        e.printStackTrace();

                    }

                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    System.out.println(error);
                }
            });
    mRequestQueue.add(request);
    mRequestQueue.start();
}

}

Answer 1

希望这有帮助。

try {    

  JSONObject joParent = response.getJSONObject(0);

  JSONObject joShow = joParent.getJSONObject("show");

  String name = joShow.getString("name");

} catch (JSONException e) {
   e.printStackTrace();
}

Answer 2

  for(int i=0; i<jArray.length(); i++) {
            JSONObject json_object = null;
            JSONObject internalObject=null;
            try {
                json_object = (JSONObject)jArray.get(i);
                internalObject= (JSONObject) json_object.get("show");
            } catch (JSONException e) {
                e.printStackTrace();
            }
            String name = null;
            try {
                name = internalObject.getString("name");
            } catch (JSONException e) {
                e.printStackTrace();
            }
            System.out.println(name);


        }

该节目是一个嵌套的JSONObject。用它替换你的for循环。

Answer 3

我已使用GSON处理您的JSON响应。

假设我们有以下模型类：

响应：

public class Response {
    @SerializedName("score")
    @Expose
    public double score;
    @SerializedName("show")
    @Expose
    public Show show;
}

显示：

public class Show {
    @SerializedName("id")
    @Expose
    public int id;
    @SerializedName("url")
    @Expose
    public String url;
    @SerializedName("name")
    @Expose
    public String name;
    @SerializedName("type")
    @Expose
    public String type;
    @SerializedName("language")
    @Expose
    public String language;
    @SerializedName("genres")
    @Expose
    public List<String> genres = new ArrayList<String>();
    @SerializedName("status")
    @Expose
    public String status;
    @SerializedName("runtime")
    @Expose
    public int runtime;
    @SerializedName("premiered")
    @Expose
    public String premiered;
    @SerializedName("schedule")
    @Expose
    public Schedule schedule;
    @SerializedName("rating")
    @Expose
    public Rating rating;
    @SerializedName("weight")
    @Expose
    public int weight;
    @SerializedName("network")
    @Expose
    public Network network;
    @SerializedName("webChannel")
    @Expose
    public Object webChannel;
    @SerializedName("externals")
    @Expose
    public Externals externals;
    @SerializedName("image")
    @Expose
    public Image image;
    @SerializedName("summary")
    @Expose
    public String summary;
    @SerializedName("updated")
    @Expose
    public int updated;
    @SerializedName("_links")
    @Expose
    public Links Links;
}

时间表：

public class Schedule {
    @SerializedName("time")
    @Expose
    public String time;
    @SerializedName("days")
    @Expose
    public List<String> days = new ArrayList<String>();
}

评分：

public class Rating {
    @SerializedName("average")
    @Expose
    public double average;
}

网络：

public class Network {
    @SerializedName("id")
    @Expose
    public int id;
    @SerializedName("name")
    @Expose
    public String name;
    @SerializedName("country")
    @Expose
    public Country country;
}

国家：

public class Country {
    @SerializedName("name")
    @Expose
    public String name;
    @SerializedName("code")
    @Expose
    public String code;
    @SerializedName("timezone")
    @Expose
    public String timezone;
}

的外部对象：

public class Externals {
    @SerializedName("tvrage")
    @Expose
    public int tvrage;
    @SerializedName("thetvdb")
    @Expose
    public int thetvdb;
    @SerializedName("imdb")
    @Expose
    public String imdb;
}

图像：

public class Image {
    @SerializedName("medium")
    @Expose
    public String medium;
    @SerializedName("original")
    @Expose
    public String original;
}

链接：

public class Links {
    @SerializedName("self")
    @Expose
    public Self self;
    @SerializedName("previousepisode")
    @Expose
    public Previousepisode previousepisode;
    @SerializedName("nextepisode")
    @Expose
    public Nextepisode nextepisode;
}

自：

public class Self {
    @SerializedName("href")
    @Expose
    public String href;
}

Nextepisode：

public class Nextepisode {
    @SerializedName("href")
    @Expose
    public String href;
}

Previousepisode：

public class Previousepisode {
    @SerializedName("href")
    @Expose
    public String href;
}

解析非常简单：

String json = ""; // Your response; for simplicity I stringified it.
Gson gson = new GsonBuilder().create();
Type showType = new TypeToken<Collection<Response>>(){}.getType();
ArrayList<Response> responses = gson.fromJson(json, showType);

for(Response response : responses) {
    Log.d("Response - json", response.toString());
}

最难的部分是，你的回答实际上是一个数组而不是对象，所以你必须parse it as described in the example。

使用上述代码的结果：

Answer 4

当您处理json并处理解析错误时，这是解决问题的最简单方法。

查找json验证器并检查json是否有效。您只需在Google上输入json validate并使用网站即可。

查看json后，name嵌套在show中。因此你真的想要

String name = json_object.getJSONObject("show").getString("name");

希望这可以解决你考虑jsons的未来问题

JSONException：解析JSONArray时不是原始数组

4 个答案:

假设我们有以下模型类：

解析非常简单：