Question

伙计们我正在尝试这个程序，我必须拿一个列表并将所有非唯一元素分开并将其放入列表而不改变它的顺序。例如[1,2,3,1,3] = [1,3,1,3]
[5,5,5,5] = [5,5,5,5]
[1,2,3,4,5] = []

所以为此，我在python中编写了程序并放了一些标志来帮助我知道我在哪里做错了。所以在程序中我试图重置list3值（在循环中删除它的一个元素之后）退出它）但它不会让我这样做。所以任何帮助将不胜感激。非常感谢你们。

list1=[1,2,3,1,3]
list2=[]
d=0
m=0
l=len(list1)
print(l)
for x in range(0,l):
    print('for loop')
    list3=list1  # I used this to reset the list3 to list1 and use it in the loop but it wouldn't reset
    print('this is the reset of list 3',list3)
    m=list1[x]
    print(m,x)
    print(list3[x])
    del (list3[x])

    while True:
        print('while loop',list3[d])

        if m==list3[d]:
            print('its here')
            list2.append(m)
            print('this is list2: ',list2)
        d+=1

        if d==lenght(list3)-1:
            print('its here22222')
            break
print(list2)

# my results were

5
for loop
this is the reset of list 3 [1, 2, 3, 1, 3]
1 0
1
while loop 2
while loop 3
while loop 1
its here
this is list2:  [1]
its here22222
for loop
this is the reset of list 3 [2, 3, 1, 3]
3 1
IndexError: list index out of range

Answer 1

这样做你想要的吗？

#list1=[5,5,5,5,5]
list1=[1,2,3,1,3]
#list1=[1,2,3,4,5]
list2=[]

for num in list1:
    if list1.count(num) > 1:
        list2.append(num)

print(list2)

列表重置为“for”循环

1 个答案: