Question

我有以下代码：

public class Screen {
...// more code
private int width, height;
public int[] pixels;

public void render(int xOffSet, int yOffSet) {
    for (int y = 0; y < height; y++) {
        int yPix = y + yOffSet;
        if (yPix < 0 || yPix >= height)
            continue;
        for (int x = 0; x < width; x++) {
            int xPix = x + xOffSet;
            if (xPix < 0 || xPix >= width)
                continue;
            pixels[(xPix) + (yPix) * width] = Sprite.grass.pixels[(x & Sprite.grass.SIZE - 1)
                    + (y & Sprite.grass.SIZE - 1) * Sprite.grass.SIZE];
        }
    }
}

这基本上会在屏幕上呈现许多相同的16x16图块。

然后我有这两种方法（在一个线程中循环）

public class Game extends Canvas implements Runnable {
    ...//more code

    public void run() {
        long lastTime = System.nanoTime();
        long timer = System.currentTimeMillis();
        final double ns = 1000000000.0 / 60.0; // Nanosegundos necesarios para
                                                // correr el juego a 60fps
        double delta = 0;
        int frames = 0;
        int updates = 0;

        while (running) {
            long now = System.nanoTime();
            delta += (now - lastTime) / ns;
            lastTime = now;
            while (delta >= 1) {
                tick();
                updates++;
                delta--;
            }
            render();
            frames++;

            if (System.currentTimeMillis() - timer > 1000) {
                timer += 1000;
                frame.setTitle(title + "\t \t FPS: " + frames + " UPS: " + updates + ".");
                frames = updates = 0;
            }
        }
        stop();
    }

    public int x = 0, y = 0;

    public void tick() {
        keyboard.tick();
        if(keyboard.up) y--;
        if(keyboard.down) y++;
        if(keyboard.left) x--;
        if(keyboard.right) x++;
    }

    public void render() {
        BufferStrategy bs = getBufferStrategy();
        if (bs == null) {
            createBufferStrategy(3);
            return;
        }

        screen.clear();

        screen.render(x, y);

        for (int i = 0; i < pixels.length; i++) {
            pixels[i] = screen.pixels[i];
        }

        Graphics g = bs.getDrawGraphics();
        g.setColor(Color.BLACK);
        g.fillRect(0, 0, getWidth(), getHeight());
        g.drawImage(image, 0, 0, getWidth(), getHeight(), null);

        g.dispose();
        bs.show();
    }
}

更新并重新渲染屏幕。

我的问题是，当我按任意键，移动屏幕时，看起来图像是“闪烁”，不会立即更新（游戏运行速度约为1000 fps，每秒60次）。有没有简单的方法来解决这个问题？

在java中更新时，防止渲染图像“闪烁”？

0 个答案: