您好我正在尝试使用以下方法执行此简单的HQL查询以从我的数据库中获取文件列表:
private static final String SQL_GET_FILE_LIST = "select filename, size, id, type from fileobject";
@Override
public List<FileObject> getFileList(String type) {
// TODO Auto-generated method stub
List<FileObject> files = hbTemplate.find(SQL_GET_FILE_LIST);
hbTemplate.flush();
return files;
}
但我一直得到这个例外:
org.hibernate.hql.ast.QuerySyntaxException: fileobject is not mapped [select filename, size, id, type from fileobject]
org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:158)
org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:87)
org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:70)
org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:257)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3056)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:2945)
org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:688)
org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:544)
org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281)
org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229)
org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:228)
org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:160)
org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:111)
org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:77)
org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:56)
org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:72)
org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:133)
org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:112)
org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1623)
org.springframework.orm.hibernate3.HibernateTemplate$30.doInHibernate(HibernateTemplate.java:923)
org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:419)
org.springframework.orm.hibernate3.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:374)
org.springframework.orm.hibernate3.HibernateTemplate.find(HibernateTemplate.java:921)
org.springframework.orm.hibernate3.HibernateTemplate.find(HibernateTemplate.java:913)
com.kc.models.DbFileHelper.getFileList(DbFileHelper.java:65)
com.kc.models.FileHelper.getFileList(FileHelper.java:108)
com.kc.Controllers.AppListController.getFileList(AppListController.java:63)
com.kc.Controllers.AppListController.handleRequest(AppListController.java:34)
org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter.handle(SimpleControllerHandlerAdapter.java:48)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:807)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:501)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
我的hbm.xml文件
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="com.kc.models.FileObject" >
<class name="com.kc.models.FileObject" table="fileobject">
<id name="id" column="ID">
<generator class="native" />
</id>
<property name="filename" type="string" column="FILENAME" />
<property name="type" type="string" column="TYPE" />
<property name="size" type="double" column="SIZE" />
<property name="file" type="blob" length="1000000000" column="FILE" />
</class>
</hibernate-mapping>
答案 0 :(得分:7)
嗯,首先,正如追踪所说,fileobject is not mapped
但是FileObject
。因此,将您的HQL查询更改为:
select filename, size, id, type from FileObject
其次,由于您正在使用投影,因此您不会获得List<FileObject>
而是List<Object[]>
。所以你的代码应该是:
private static final String SQL_GET_FILE_LIST = "select filename, size, id, type from FileObject";
@Override
public List<Object[]> getFileList(String type) {
// TODO Auto-generated method stub
List<Object[]> files = hbTemplate.find(SQL_GET_FILE_LIST);
hbTemplate.flush();
return files;
}
或者,如果要获得类型安全的结果,可以使用构造函数表达式(假设您的类提供了适当的构造函数):
select new FileObject(filename, size, id, type) from FileObject
然后你可以使用你当前的代码。
private static final String SQL_GET_FILE_LIST = "select new FileObject(filename, size, id, type) from FileObject";
@Override
public List<FileObject> getFileList(String type) {
// TODO Auto-generated method stub
List<FileObject> files = hbTemplate.find(SQL_GET_FILE_LIST);
hbTemplate.flush();
return files;
}
答案 1 :(得分:3)
您指定的是表名,而不是类名;他们的情况有所不同。试试这个:
private static final String SQL_GET_FILE_LIST =
"select filename, size, id, type from FileObject";
不可否认,自从我做了任何Hibernate以来已经有一段时间了,但我怀疑这就是问题......