Question

这是我正在执行的代码（简化为最小的工作示例）：

#include <cstdio>   

static unsigned long long n = 4;
static unsigned long long k = 4;

int main() {

    for (unsigned long long i = 2; i < k; ++i) {
        for (unsigned long long j = 2; j < n; ++j) {

            unsigned long long* v = new unsigned long long[j];

            for (unsigned long long h = 0; h < j; ++i)
                v[h] = h + 1;

            delete[] v;
        }
    }

    return 0;
}

当我运行此代码时，它不会终止。使用gdb似乎卡在指令unsigned long long* v = new unsigned long long[j]上。使用display命令，j的值为2。

我的问题是它为什么会被困在那条线上。

gdb信息

Reading symbols from main...done.
(gdb) disp n
1: n = <optimized out>
(gdb) disp k
2: k = 4
(gdb) break main
Breakpoint 1 at 0x400a80: file main.cpp, line 6.
(gdb) run Starting program: /home/user/cpp/main 

Breakpoint 1, main () at main.cpp:6
6   int main() {
2: k = 4
1: n = <optimized out>
(gdb) s
11  unsigned long long* v = new unsigned long long[j];
2: k = 4
1: n = <optimized out>
(gdb) disp j
3: j = 2
(gdb) s

被困在这里。

Answer 1

你在内循环中增加i而不是h

坚持创建无符号长长数组

1 个答案: