如何添加数据两个列添加后添加两个添加下一个

Question

我有以下查询我想添加两条记录，如16 + 16 = 32 + 15 = 47这样我想要30 + 15，= 47 + 15这样，

USE [ItemTable]
GO
/****** Object:  Table [dbo].[NewPriceLabel]    Script Date: 05/07/2016 03:46:58 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
SET ANSI_PADDING ON
GO
CREATE TABLE [dbo].[NewPriceLabel](
    [PLU] [varchar](25) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
    [Description] [varchar](40) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [Sizes] [varchar](7) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [OldPrice] [real] NULL,
    [NewPrice] [real] NULL,
    [Datechange] [datetime] NOT NULL CONSTRAINT [NewPriceLabel_Datechange]  DEFAULT (getdate()),
    CONSTRAINT [PK_NewPriceLabel] PRIMARY KEY CLUSTERED (
        [PLU] ASC,
        [Datechange] ASC
)WITH (PAD_INDEX  = OFF, IGNORE_DUP_KEY = ON) ON [PRIMARY]) ON [PRIMARY]

GO
SET ANSI_PADDING OFF

Answer 1

我不是100％肯定你在问什么，但听起来你想要一笔累计金额。这个问题已经得到了回答：

https://stackoverflow.com/a/2120639/2565840

编辑：在您的情况下，我认为下面的查询应该有效

WITH    
rows AS (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY gps_time) AS rn
        FROM    rawtTackHistory_A2Z where car_id = 12956 
),
differences AS (
    SELECT  mc.rn, mc.gps_time,DATEDIFF(second, mc.gps_time, mp.gps_time) time_diff
    FROM    rows mc
    JOIN    rows mp
    ON      mc.rn = mp.rn - 1
)
SELECT t1.gps_time, t1.time_diff, SUM(t2.time_diff) time_sum
FROM differences t1
INNER JOIN differences t2 
ON t1.rn >= t2.rn
GROUP BY t1.rn, t1.gps_time, t1.time_diff
ORDER BY t1.rn

或者如果您正在使用SQL Server 2012或更高版本，则应该更快地运行：

SELECT gps_time
     , DATEDIFF(second, LAG(gps_time) OVER (ORDER BY gps_time), gps_time) time_diff
     , DATEDIFF(second, MIN(gps_time) OVER (ORDER BY gps_time), gps_time) time_sum
FROM rawtTackHistory_A2Z 
ORDER BY gps_time

它使用了一个窗口子句（OVER）。更多细节：https://msdn.microsoft.com/en-us/library/ms189461.aspx