我在使用jQuery滚动到.content-single时添加了class active。我还想在动态添加活动类的基础上为#with-scroll添加不同的类。
这是我的HTML
<div id="with-scroll" class="single with-scroll">
<div class="row">
<div class="outer-navigator"><a href="#" class="tl-navigator three">3</a></div>
<div class="col s12 center-align third-title">
<h2>Lorem ipsum dolor sit amet</h2>
</div>
<div class="col m6 s6">
<div class="text-content">
<h3>Lorem ipsum,<br>
in real time.</h3>
<div id="content-single-one" class="content-single">
<a href="#scroll1"></a>
<i class="material-icons">supervisor_account</i>
<h4 id="scroll1" class="section scrollspy">Lorem ipsum dolor sit amet</h4>
<p>Lorem ipsum, your workers, your team and
companies perform side by side - in real-time.</p>
</div>
<div id="content-single-two" class="content-single">
<a href="#scroll2"></a>
<i class="material-icons">av_timer</i>
<h4 id="scroll2" class="section scrollspy">Lorem ipsum</h4>
<p>Lorem ipsum with the help of screenshotting,<br>
screen recording orem ipsum monitoring.<br>
Know exactly what was done and when.
</p>
</div>
<div id="content-single-three" class="content-single">
<a href="#scroll3"></a>
<i class="material-icons">group_work</i>
<h4 id="scroll3" class="section scrollspy">Lorem ipsum</h4>
<p>Lorem ipsum, your worers, team and compa nies <br>
perform side-by-side - in real-time. <br>
Iden tify bottlenecksand getan eagle-eye view <br>
of your business. </p>
</div>
</div>
</div>
<div class="col m6 s6" id="screen-sticky">
<div class="screen">
<img src="images/macbook.png">
<div class="inner one">
<img src="images/screen-1.png">
</div>
<div class="inner two">
<img src="images/screen-2.png">
</div>
<div class="inner three">
<img src="images/screen-3.png">
</div>
</div>
</div>
</div>
</div>
这是Jquery我想选择
$(function() {
$("#content-single-one.active").each(function(){
$("#with-scroll").addClass("one");
});
$("#content-single-two.active").each(function(){
$("#with-scroll").addClass("two");
});
$("#content-single-three.active").each(function(){
$("#with-scroll").addClass("three");
});
});
答案 0 :(得分:2)
您可以验证该课程是否有效
$(document).scroll(function(){
if($("#content-single-one").hasClass('active')){
$("#with-scroll").addClass("one");
}else if($("#content-single-two").hasClass('active')){
$("#with-scroll").addClass("two");
}else if($("#content-single-three").hasClass('active')){
$("#with-scroll").addClass("three");
}
})
答案 1 :(得分:0)
这对我有用。您应该修改您的代码:
$(document).on('change', 'yourSelectingClassId', function(){
//your code...
});
我认为添加会很好。因为我尝试了很多方法,所以终于奏效了。我希望有需要的人都能看到它。