Question

我怎样才能获得像这样的简单JSON结构

{
    "id": 9901,
    "name": "Reader",
    "value": true
}

使用JAXB注释和那段代码？（UserInfo应包含相同层次结构级别的枚举字段）

@XmlRootElement
public class UserInfo
{
    private UserLevel level;

    @XmlElement ( name = "value" )
    private boolean allowed;
}

public enum UserLevel
{
    READER ( "Reader", 9901 ),
    TESTER ( "Tester", 9903 );

    private final String name;
    private final int id;

    private UserLevel( String name, int id )
    {
       this.name = name;
       this.id = id;
    }

    get...()
}

Answer 1

一个解决方案是让另一个JAXB类与你想要的JSON结构相匹配，就像这样（缺少构造函数）：

@XmlRootElement
public class UserInfoFlattened
{
    @XmlElement
    private int id;

    @XmlElement
    private String name;

    @XmlElement ( name = "value" )
    private boolean allowed;
}

然后你应该在课程@XmlJavaTypeAdapter上使用UserInfo，它看起来像这样：

public class UserInfoAdapter extends XmlAdapter<UserInfoFlattened, UserInfo>
{
    @Override
    public UserInfoFlattened marshal( UserInfo userInfo )
    {
        return new UserInfoFlattened( userInfo.getValue(), userInfo.getUserLevel().getId(), userInfo.getUserLevel().getName() );
    }

    // unmarshal analogous
}

JAXB将枚举添加为扁平结构

1 个答案: