Question

我有这本名为传记的词典

self.biography = {'Name' : '', 'Age' : 0, 'Nationality' : '', 'Position' : 0, 'Footed' : ''}

我也有这个叫做create_player

的方法

def create_player(self):
    name = input('Player name: ')
    age = int(input('Player age: '))
    nationality = input('Nationality: ')
    position = input('Position: ')
    footed = input('Footed: ')

如何浏览此列表并附加到传记字典中，相应地将各种属性名称与其值相匹配

Answer 1

def create_player(self):
    for key in self.biography.keys():
        val = input('Player {}: '.format(key.lower()))
        self.biography[key] = int(val) if val.strip().isdigit() else val

Answer 2

def create_player(self):
    self.biography['Name'] = input('Player name: ')
    self.biography['Age'] = int(input('Player age: '))
    self.biography['Nationality'] = input('Nationality: ')
    self.biography['Position'] = input('Position: ')
    self.biography['Footed'] = input('Footed: ')

试试这个。

Answer 3

def create_player(self):
    name = input('Player name: ')
    age = int(input('Player age: '))
    nationality = input('Nationality: ')
    position = input('Position: ')
    footed = input('Footed: ')

    # afterwards
    self.biography["Name"] = name
    self.biography["Age"] = age
    ... and so on ...

只需访问biography dict，就像（关联）数组一样如果您想要有序输出，请使用OrderedDict，如下所示：

from collections import OrderedDict

class myClass():
    biography = OrderedDict()
    def setupDict(self):
        self.biography["Name"] = "Some name here"

从方法附加到Python字典

3 个答案: