Question

我希望在每个数组的索引的帮助下获得下面的三个JSONArrays 我的JSON：

 {
  [
    {
      "id": 3429,
      "name": "Mass Effect: Andromeda",
      "prix": 100,
      "description": "The newest Mass Effect instalement",
      "quantiteDisponible": 400,
      "image": "https://res.cloudinary.com/igdb/image/upload/t_screenshot_big/xtn9vhiek0kdpetibmvw.webp"
    },
    {
      "id": 3430,
      "name": "Halo 5: Guardians",
      "prix": 10,
      "description": "Not the best Halo",
      "quantiteDisponible": 420,
      "image": "https://res.cloudinary.com/igdb/image/upload/t_cover_big/rzjnrhuv5rozj52g9aq3.webp"
    }
  ],
  [
    {
      "id": 3431,
      "name": "Bloodbonrne",
      "prix": 20,
      "description": "Better than you",
      "quantiteDisponible": 612,
      "image": "https://res.cloudinary.com/igdb/image/upload/t_cover_big/fivw1ogfjw266t72kcn2.webp"
    },
    {
      "id": 3432,
      "name": "Dark Souls 3",
      "prix": 60,
      "description": "Prepare to die",
      "quantiteDisponible": 604,
      "image": "https://res.cloudinary.com/igdb/image/upload/t_cover_big/ofu6ewg0tzdt5vmzcj9q.webp"
    }
  ],
  [
    {
      "id": 3433,
      "name": "Mario Sunshine",
      "prix": 40,
      "description": "Mario Sunshine best Mario Game",
      "quantiteDisponible": 11,
      "image": "https://res.cloudinary.com/igdb/image/upload/t_cover_big/ok5aq7j375uaxp59zr2g.webp"
    },
    {
      "id": 3434,
      "name": "Outlaw Golf",
      "prix": 60,
      "description": "Outlaw Golf is back with a bang!",
      "quantiteDisponible": 10,
      "image": "https://res.cloudinary.com/igdb/image/upload/t_cover_big/cxgtamh2r6z7tezfs1og.webp"
    }
  ]
}

我不知道是否有可能并且非常感谢任何帮助首先，我将JSON存储为变量：

JSONObject object = new JSONObject(JsonText);
System.out.println(object.length());

System.out.println返回3，因此它知道我们正在讨论3个JSON数组。

这就是我如何尝试获取数组

for (int i = 0; i < object.length(); i++){
        JSONArray array = object.getJSONArray(HELP);

}

Answer 1

你可以尝试这个片段

for (int i = 0; i < getArray.length(); i++) {
        JSONObject objects = getArray.getJSONObject(i);
        Iterator key = objects.keys();
        while (key.hasNext()) {
            String k = key.next().toString();
            System.out.println("Key : " + k + ", value : "
                    + objects.getString(k));
        }
        // System.out.println(objects.toString());
        System.out.println("-----------");

    }

Answer 2

你必须传递i的值。但是object.getJSONArray（）只接受string.So你可以像这样使用。

    JSONObject obj=new JSONObject(JsonText);
    for(int i=0;i<obj.length();i++){

        try {
            JSONArray jsonArray=obj.getJSONArray(String.valueOf(i));
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

如何在JSONObject中获取没有名称的JSONArrays

2 个答案: