我想创建数组:
$branza_query = mysql_query ('SELECT craft FROM base') or die...
$craft = array();
while ($cra = mysql_fetch_array($craft_query))
{
$craft[] = $cra;
}
没什么大不了的,但是当我想print_r
它时,我会像以前一样:
Array ( [0] => Array ( [0] => steel [craft] => steel )
[1] => Array ( [0] => farm [craft] => farm )
[2] => Array ( [0] => some [craft] => some )
[3] => Array ( [0] => it [craft] => it ) // etc.
)
我只是想在现有数组中添加下一个值,结果如下:
Array ( [0] = steel
[1] = farm
[2] = some
[3] = it /etc.
)
或
Array ( [0] = craft => steel
[1] = craft => farm
[2] = craft => some
[3] = craft => it /etc.
)
或类似的东西,因为接下来的事情我想做的是:
foreach($craft as $value)
{
echo '<option value ="'.$value.'"> '.$value.'</option>';
}
答案 0 :(得分:0)
问题是,每次调用$cra
时,您都会创建一个数组$craft[]=$cra
作为其第一个元素,然后将其添加到$craft
。这就是为什么你有一个三层数组。
但实际上,$cra
已经是一个数组。所以你需要做的只是array_push($craft, $cra);
。或者使用array_push($craft, $cra[0]);
这将提供您想要的内容。
请参阅页面http://php.net/manual/en/function.mysql-fetch-array.php