Question

$a = array('2016-05-06', '2016-05-08', '2016-05-20', '2016-05-23');

foreach($a as $key => $value){
   $dateFrom = $value //2016-05-06 Then 2016-05-20
   $dateTo = $value //2016-05-08 Then 2016-05-23

   function range($dateFrom, $dateTo);
} //in the second loop get the others 2 like above

重点是传递第一个和最后一个日期并制作一个范围

最终获得这样的数组

Array
(
    [0] => 2016-05-06
    [1] => 2016-05-07
    [2] => 2016-05-08
    [3] => 2016-05-20
    [4] => 2016-05-21
    [5] => 2016-05-22
    [6] => 2016-05-23
)

我得到了第一个数组，现在问题在于使用4个日期的范围

foreach(array_slice($dates, 2) as $key => $value){
     $a[] .= $datas[$key];

     if($key == 0){
         $a[] .= $value;
     } else {
         $a[] .= $value; 
     }
}

Answer 1

使用DatePeriods执行此操作的一种方法：

$ranges = array_chunk($dates, 2);          // Divide the array into groups of two

$interval = new DateInterval('P1D');       // Define an interval of one day

foreach ($ranges as $range) {
    // Create DateTime objects for the start and end dates
    $start = new DateTime($range[0]);
    $end = new DateTime($range[1]);
    $end->add($interval);

    // Create a new DatePeriod object using the start and end DateTime objects
    $period = new DatePeriod($start, $interval, $end);

    // Iterate over the DatePeriod to fill your result array
    foreach ($period as $date) {
        $result[] = $date->format('Y-m-d');
    }
}

Answer 2

是的......这是可能的，这就是我想象你想要的：

            <?php
            $a                  = array('2016-05-06', '2016-05-08', '2016-05-20', '2016-05-23');
            $arrDuos            = array();

            $arrTempRange       = array();
            foreach($a as $intKey=>$dateVal){
                $arrTempRange[]     = $dateVal;
                if($intKey != 0 && $intKey%2){
                    $arrDuos[]      = $arrTempRange;
                    $arrTempRange   = array();
                }
            }

            $arrArrangedDate    = array();
            foreach($arrDuos as $intKey=>$arrDateRange){
                $startDate      = $arrDateRange[0];
                $endDate        = $arrDateRange[1];
                $dateDiff   = date_diff( date_create($endDate), date_create($startDate) )->days;
                for($i = 0; $i<=$dateDiff; $i++){
                    $incrementedDate    = strtotime($startDate) + (60*60*24*$i);
                    $arrArrangedDate[]  = date("Y-m-d", $incrementedDate); 
                }
            }

            // MANUALLY APPEND THE LAST ELEMENT OF THE ARRAY TO THE 
            // RESULTANT ARRAY IF THE ARRAY LENGTH IS ODD LIKE SO:    
            if(count($a)%2){
                $arrArrangedDate[] = end($a);
            }

            var_dump($arrArrangedDate);

转储：

       array (size=7)
          0 => string '2016-05-06' (length=10)
          1 => string '2016-05-07' (length=10)
          2 => string '2016-05-08' (length=10)
          3 => string '2016-05-20' (length=10)
          4 => string '2016-05-21' (length=10)
          5 => string '2016-05-22' (length=10)
          6 => string '2016-05-23' (length=10)

我希望这能回答你的问题...; - ）

有可能像这样打破阵列吗？

2 个答案: