Question

我在文件中得到的文字与此类似。

OVM>
show PhysicalDisk id='12346579123456789123456789'
Data:
  Page83 ID = OVM_SYS_REPO_PART_12346579123456789123456789
  Server Reserved = No
  Shareable = No
  Size (GiB) = 503.37
  State = UNKNOWN
  Thin Provision = No
  Type = LUN
  User-Friendly Name = 200173800eeec23ff
  Vendor = Lenovo
  File System 1 = 12346579123456789123456789
  Volume Group = 12346579123456789123456789  [Local Storage Volume Group]
  Id = 12346579123456789123456789 [OVM_SYS_REPO_PART_12346579123456789123456789]
  Name = OVM_SYS_REPO_PART_12346579123456789123456789
  Locked = false
OVM>
show PhysicalDisk id='123465791234567891234567892'
Data:
  Storage Targets 1 = 0x50017380eeec0140
  Storage Targets 2 = 0x50017380eeec0170
  Storage Targets 3 = 0x50017380eeec0150
  Storage Targets 4 = 0x50017380eeec0172
  Storage Targets 5 = 0x50017380eeec0152
  Storage Targets 6 = 0x50017380eeec0182
  Page83 ID = 200173800eeec23aa
  Server Reserved = No
  Shareable = Yes
  Size (GiB) = 16.03
  State = UNKNOWN
  Thin Provision = Yes
  Type = LUN
  User-Friendly Name = 200173800eeec23aa
  Vendor = IBM
  File System 1 = 123465791234567891234567892  [Server Pool File System]
  Volume Group = 123465791234567891234567892  [FibreChannel Volume Group]
  Id = 123465791234567891234567892  [Production Quorum LUN]
  Name = Production LUN
  Locked = false
OVM>

我只想选择＆＃34;用户友好名称＆＃34;，＆＃34;尺寸＆＃34;和＆＃34;姓名＆＃34;每个输出的行（对于每个＆＃34;显示＆＃34;）并像这样加入它们。

用户友好名称= 200173800eeec23aa名称=生产LUN大小（GiB）= 16.03

事实上，如果我能得到它会更好：

200173800eeec23aa Production LUN 16.03

我尝试了这个但是由于某种原因它在每一行之间粘贴\ n而不是在3种模式的末尾：

awk 'match($0, /(User.*)|(Name.*)|(Size.*)/, a) {printf "%s %s %s\n", a[1], a[2], a[3]}' object_data/LUNs.txt

所以我实际上得到了（包括那个奇怪的身份）：

User-Friendly Name = 200173800eeec23aa
 Name = Production LUN
  Size (GiB) = 16.03

我该如何解决这个问题？非常感谢你。

Answer 1

以下是适合您情况的awk脚本：

<强> script.awk：

BEGIN {FS="="}
$1 ~ "User-Friendly Name" { ufn = $2 }
$1 ~ "Size" { sz = $2 }
$1 ~ "Name" { printf("%s%s%s\n",ufn,$2, sz) }

像awk -f script.awk yourfile一样使用它。

输出说明：每行匹配本身。例如，包含Size的行与原始awk脚本中的第二个括号匹配。该行仅包含“Size（GiB）...”：所以：

a[1]和a[3]为空
a[2] 整行（由于.*）
换行符是\n

printf

Answer 2

惯用的awk方法：

$ awk -F' = ' '
   { gsub(/^ +| +\([^)]+\)$/,"",$1); m[$1]=$2 }
   NR>1 && /^OVM/{ print m["User-Friendly Name"], m["Name"], m["Size"] }
' file
200173800eeec23ff OVM_SYS_REPO_PART_12346579123456789123456789 503.37
200173800eeec23aa Production LUN 16.03

Answer 3

只需删除每行末尾的'\ n'：gsub（/ [\ n] $ /，“”，$ 0）

如何将3个模式作为一行与awk连接

3 个答案: