Question

如果这是转贴，我很抱歉。但是我没有找到正确答案就看到了很多问题我正在尝试上传多个文件+一些信息，但如果我提交我的表格有2个图像就可以了，脚本运行完美，当我上传2或3个文件时，我得到所有表单元素的未定义索引。

up.php

   /////// Random name generator ////////
function random_name($length) {
$key = '';
$keys = array_merge(range(0, 9), range('a', 'z'));

for ($i = 0; $i < $length; $i++) {
    $key .= $keys[array_rand($keys)];
}

   return $key;
}

 //sql//
  require("sql.php");
 //////////
 //!!! some vars !!!//
 //
     $total = count($_FILES['pimages']['name']);
 //
 $foldername = random_name(15);
  $target_dir = "../images/projects/".$foldername."/";
   $target_file = $target_dir . basename($_FILES["icon"]["name"]);
     $uploadyes = 1;
    $imageType = pathinfo($target_file,PATHINFO_EXTENSION);
   $saveicon = $target_dir . "icon." .$imageType;

    /////submited form vars /////

  $linkedid = $_POST['lid'];

  $date = date("y.m.d H:i:s");
  $name = $_POST['projectname'];
  $loc = $_POST['location'];
  $type = $_POST['type'];
  $des = $_POST['des'];
  $precara = $_POST['cara'];
  $client = $_POST['client'];
  $col = $_POST['cost'];
  $bua = $_POST['builtup'];

  ////////////////cara slice /////////////
  $caraxarray = explode("," , $precara);
  $cara = base64_encode(serialize($caraxarray));









  echo $imageType ;




  ///////////////////////// Start of the upload check ////////////////////
    if(isset($_POST['submit']) && !empty($name)) {
   $conn = mysqli_connect($servername, $username, $password, $dbname);
   // Check connection
  if (!$conn) {
      die("Connection failed: " . mysqli_connect_error());
  } 
 }










     // Check if $uploadyes is set to 0 by an error
    if (!isset($_POST['submit'])) {
       echo "Sorry, your file was not uploaded.";
  // if everything is ok, try to upload file
   } else {
      mkdir($target_dir);



      if (move_uploaded_file($_FILES["icon"]["tmp_name"], $saveicon)) {
             //////////////////////////..........................//////////////////
      // Loop through each file
    $imgext = array();
    for($i=0; $i<=$total; $i++) {
     //Get the temp file path
    $tmpFilePath = $_FILES['pimages']['tmp_name'][$i];

    $x = $i + 1 ;
    if ($tmpFilePath != ""){
     //Setup our new file path
  $pimgex = $_FILES['pimages']['name'][$i];

  $pimageType = pathinfo($pimgex,PATHINFO_EXTENSION);

  $newFilePath = $target_dir ."img".$x.".".$pimageType;
  array_push($imgext , "$newFilePath");
      //Upload the file into the temp dir
    if(move_uploaded_file($tmpFilePath, $newFilePath)) {

       echo "yeaaaaaah";

     }
   }
 }
   $str = serialize($imgext);
   $sql1 = "INSERT INTO projects (date, name, type, location, icon, imgext, folder, linkedid)
    VALUES ('$date', '$name','$type', '$loc', '$saveicon' , '$str', '$foldername',   '$linkedid')";
 $sql2 = "INSERT INTO projectdetails (proname, prolocation, prodes, procara,      client, col, builtarea, linkedid)
 VALUES ('$name', '$loc','$des', '$cara', '$client' , '$col', '$bua',         '$linkedid')";
    mysqli_query($conn ,$sql1);
    mysqli_query($conn ,$sql2);
    mysqli_close($conn);
/////////////////...........................////////////////////////
        header("location:cp.php");
    } else {
    echo "Sorry, there was an error uploading your file.";
    }
}

projectsuploader.php

   $lkid = random_name(8);
 $tlink = random_name(6);
 require("sql.php");
 // Create connection
 $conn = mysqli_connect($servername, $username, $password, $dbname);
 // Check connection
 if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

   $sql1 = "SELECT id, date, name, type, location FROM projects";
   $sql2 = "SELECT id, titleen FROM projectsnav";
   $result = mysqli_query($conn, $sql1);
   $types = mysqli_query($conn, $sql2);



        //mysqli_close($conn);   

      ?>
      <!DOCTYPE html>
     <html>

   <h2>Projects Page</h2>

   <h5>projects</h5>
   <table>
   <tr>
   <td>#</td>
   <td>Date & Time</td>
   <td>Project name</td>
  <td>Project type</td>
   <td>Project location</td>
 <!--<td>View</td>
 <td>Edit</td>-->
   <td>Remove</td>
  </tr>
   <?php

  if (mysqli_num_rows($result) > 0) {
     // output data of each row .$row["id"]
     while($row = mysqli_fetch_assoc($result)) {
        echo "<tr><td>".$row["id"]."</td>";
        echo "<td>".$row["date"]."</td>";
        echo "<td>".$row["name"]."</td>";
        echo "<td>".$row["type"]."</td>";
        echo "<td>".$row["location"]."</td>";
        echo "<td><a href='../del.php?id=".$row['id']."'>Remove</a></td>         </tr>";
     }
    } else {
     echo "0 results";
    }
     mysqli_close($conn);
   ?>
   </table>
   <h4 id="addproject">Add Project</h3>
   <h4 id="addtype">Add Type </h4>
   <div id="frontlayer">
  <div id="addpro">
  <h2 style="text-align:center;"> add project </h2>
   <form method="POST" action="up.php" enctype="multipart/form-data" >
    <input type="hidden" name="MAX_FILE_SIZE" value="50000000">
   id:<input type="text" name="lid" value="<?php echo $lkid ; ?>" readonly>    <br>
    project name:<input type="text" name="projectname"><br>
    Type:<select name="type">

     <?php
     if (mysqli_num_rows($types) > 0){
     while($navrow = mysqli_fetch_assoc($types)) {
        echo "<option value='".$navrow['titleen']."'>".$navrow['titleen']."     </option>";
    }
    }else{
        echo "<option>PLEASE ADD TYPES TO DATABASE FIRST!!!!ERROR 0 TYPES IN       DATABASE</option>";
    }

   mysqli_close($conn);
   ?>

  </select>
<br>
  location:<input type="text" name="location"><br>
  icon:<input type="file" name="icon" id="icon"><br>
 images:<input type="file" name="pimages[]" id="pimages" multiple><br>
 <input type="hidden" name="sendfiles" value="Send Files" />
 <!--
 ------//////////////------
 ------//////////////------
 ------//////////////------
 -->
 description:<input type="text" name="des"><br>
 caracteristic:<input type="text" name="cara" data-role="tagsinput"><br>
 client:<input type="text" name="client"><br>
Collaborator:<input type="text" name="cost"><br>
Gross Area:<input type="text" name="builtup"><br>

<input type="submit" value="Upload" name="submit">

</form>
</div>

对不起，如果它是坏的，我是乞丐，请提前感谢任何帮助

Answer 1

问题是有一个大文件（4mb图像）并且php无法发布此图像大小的图像，因此您必须在上传之前调整图像大小。非常感谢Felippe Duarte。

无法上传表单中的多个文件

1 个答案: