Question

为什么在按照xpath打开第一个元素后循环不起作用？我得到以下异常

 raise exception_class(message, screen, stacktrace)
 selenium.common.exceptions.NoSuchElementException: Message: Unable to
 locate element:{"method":"xpath","selector":"//[@id='searchresults']/tbody/tr[2]/td[1]"}
 Stacktrace:
at FirefoxDriver.prototype.findElementInternal_ (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/driver-component.js:10723)
at FirefoxDriver.prototype.findElement (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/driver-component.js:10732)
at DelayedCommand.prototype.executeInternal_/h (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/command-processor.js:12614)
at DelayedCommand.prototype.executeInternal_ (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/command-processor.js:12619)
at DelayedCommand.prototype.execute/< (file:///c:/users/home/appdata/local/temp/tmpeglp49/extensions/fxdriver@googlecode.com/components/command-processor.js:12561)

代码：

from selenium import webdriver
from texttable import len
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
driver=webdriver.Firefox()
driver.get('https://jobs.ericsson.com/search/')
driver.maximize_window()
driver.find_element_by_css_selector('[type="text"][id="keywordsearch-q"]').send_keys('Python')
driver.find_element_by_css_selector('[class="btn"][type="submit"]').click()
i=len("//*[@id='searchresults']/tbody/tr/td")
for j in range(1,i+1):
   driver.find_element_by_xpath("//*[@id='searchresults']/tbody/tr[%d]/td[1]"%j).click()
   print driver.find_element_by_id("job-title").text
   driver.back()
   continue

问题2：为什么列表的长度显示为12，但它们只有5个herf元素？

from selenium import webdriver
from texttable import len
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
driver=webdriver.Firefox()
driver.delete_all_cookies()
driver.get('https://jobs.ericsson.com/search/')
driver.maximize_window()
driver.find_element_by_css_selector('[type="text"][id="keywordsearch-q"]').send_keys('Python')
driver.find_element_by_css_selector('[class="btn"][type="submit"]').click()
#currenturl = driver.current_url
pages=driver.find_elements_by_css_selector('a[rel="nofollow"]')
print pages
print 'Its working'
pages1=[]
for page1 in pages:
  pages1.append(page1.get_attribute('href'))
  print int(len(pages1))

问题3：如何获取html标签下的元素

a。如何在b标签下分别获得1-25和104？

请参阅网址：https://jobs.ericsson.com/search/?q=Python（结果部分显示在页面底部）

<div class="paginationShell clearfix" lang="en_US" xml:lang="en_US">
<div class="pagination well well-small">
<span class="pagination-label-row">
<span class="paginationLabel">
 Results 
 <b>1 – 25</b>
   of 
 <b>104</b>
 </span>

b。如何从html获取作业ID？

 <div class="job">
<span itemprop="description">
<b>Req ID:</b>
 128378
<br/>
<br/>

Answer 1

请尝试以下：

for job in range(len(driver.find_elements_by_class_name('jobTitle-link'))):
    driver.implicitly_wait(5)
    driver.find_elements_by_class_name('jobTitle-link')[job].click()
    print driver.find_element_by_id("job-title").text
    driver.back()

Answer 2

这可能对您有所帮助，但根据我自己的经验，当我的页面未完全加载时，我通常会遇到此错误。在搜索元素之前添加time.sleep(1) 通常为我解决了问题（如果代码正确的话）。

import time

#Skip your other code

for j in range(1,i+1):
   time.sleep(1)
   driver.find_element_by_xpath("//*[@id='searchresults']/tbody/tr[%d]/td[1]"%j).click()
   print driver.find_element_by_id("job-title").text
   driver.back()
   continue

Answer 3

这是一个有效的解决方案，其想法不是点击每个链接而是将网址存储在列表中然后导航到它：

from selenium import webdriver
from texttable import len
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait

driver=webdriver.Firefox()
driver.get('https://jobs.ericsson.com/search/')
driver.maximize_window()
driver.find_element_by_css_selector('[type="text"][id="keywordsearch-q"]').send_keys('Python')
driver.find_element_by_css_selector('[class="btn"][type="submit"]').click()

#To further process preserve the current url    
currenturl = driver.current_url
#Get all the elements by class name
jobs  = driver.find_elements_by_class_name('jobTitle-link')
jobslink = []
#Get hyperlink urls from the jobs elements
#This way we avoid clicking each link and going back to the previous page
for job in jobs:
    jobslink.append(job.get_attribute('href'))
#Get each element page  
for job in jobslink:
    driver.get(job)
    print driver.find_element_by_id("job-title").text

Python selenium代码不起作用

3 个答案: