$('#formName').on('submit', function(e){
e.preventDefault();
$.ajax({
url: "file.php",
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData: false,
beforeSend: function(){
// do something
},
uploadProgress: function(event, position, total, percentComplete){
// do something
}
})
.done(function(data){
// do something
})
.fail(function(data){
// do something
})
});
In above code, when actual data/statements are processed then beforeSend() & the uploadProgress() function are not working at all. Please help me understand the problem. Might the code structure is wrong or I'm missing few things within this code itsef.
答案 0 :(得分:0)
像js这样的引用见enter link description here
$(function() {
var bar = $('.bar');
var percent = $('.percent');
var status = $('#status');
$('form').ajaxForm({
beforeSend: function() {
status.empty();
var percentVal = '0%';
bar.width(percentVal);
percent.html(percentVal);
},
uploadProgress: function(event, position, total, percentComplete) {
var percentVal = percentComplete + '%';
bar.width(percentVal);
percent.html(percentVal);
},
complete: function(xhr) {
status.html(xhr.responseText);
}
});
});

<form action="file-echo2.php" method="post" enctype="multipart/form-data">
<input type="file" name="myfile"><br>
<input type="submit" value="Upload File to Server">
</form>
<div class="progress">
<div class="bar"></div >
<div class="percent">0%</div >
</div>
<div id="status"></div>
&#13;
答案 1 :(得分:0)
首先,谢谢所有回答我问题的人,我真的很感激。现在,经过编码和测试,测试和编码等等......我想出了一个解决我自己问题的方法。作为一个机会,我想与大家分享。所以这里是::
uploadProgress
不是parameter
的{{1}},因此我无法使用它,因为我试图使用它的第一个片段。.ajax() method
来完成任何类型的工作,比如上传/下载等等,该怎么办?因此,问题的答案是uploadProgress
来处理xhr: function()
中的所有XMLHttpRequest()
。所以,希望这些信息在任何情况下都可以帮到你。如果
YES
请回答这个答案:D - 祝你有个美好的一天!