Question

我有聊天服务，所以：

select k.user, c.id, c.from, c.sent, c.message, c.recd from chat c
inner join cadastro k on c.from=k.id
where (`from`=? and `to`=?)
order by c.id
limit 50

我想显示最近50条消息，如果我发送1到100，它将显示：

我想显示最近50条这样的消息：

50
51
...
100

如果我把order by c.id desc给我订单：

任何想法？

Answer 1

select * from
(
  select k.user, c.id, c.from, c.sent, c.message, c.recd from chat c
  inner join cadastro k on c.from=k.id
  where (`from`=? and `to`=?)
  order by c.id desc
  limit 50
) tmp
order by id asc

Answer 2

我不确定这是最有效的方法，但您可以尝试：

SELECT A.user, A.id, A.from, A.sent, A.message, A.recd
FROM (
   select TOP 50 k.user, c.id, c.from, c.sent, c.message, c.recd from chat c
   inner join cadastro k on c.from=k.id
   where (`from`=? and `to`=?)
   order by c.id DESC
) AS A
ORDER BY c.id ASC

按顺序排序不按正确的顺序显示

2 个答案: