Question

因为标题暗示我的算法用于将数值转换为字符串存在问题。我可以达到一定数量，但一旦我达到100美元，程序就会崩溃。我对一些价值观也差不多几美分，所以我想知道我能做些什么来改变它。

这是我的头文件

#include <sstream>
#include <iostream>
#include <iomanip>
#include <string>
#include <string.h>
using namespace std;

class TextVersionOfNumber
{
private:
    double amount;
public:
    string getTextVersionOfNumber();
    void setAmount(double);
};

这是我的.cpp文件（这是算法所在的位置）

#include "TextVersionOfNumber.h"


string TextVersionOfNumber::getTextVersionOfNumber()
{
    string upto20[20] = { "", "one", "two", "three", "four",
        "five", "six", "seven", "eight", "nine", "ten",
        "eleven", "twelve",
        "thirteen", "fourteen", "fifteen", "sixteen", "seventeen",
        "eighteen", "nineteen" };

    string ten_ninety[10] = { "", "", "twenty", "thirty", "forty",
        "fifty", "sixty", "seventy", "eighty", "ninety" };

    double _amount1 = (int)amount;
    double _amount2 = (amount - _amount1) * 100;

    string str_one = "";

    if (_amount1 <= 19)
    {
        str_one = upto20[(int)_amount1];
    }
    else
    {
        int tens = _amount1 / 10;
        int ones = _amount1 - (tens * 10);
        str_one = ten_ninety[tens] + upto20[ones];
    }

    string str_two = "";

    if (_amount2 <= 19)
    {
        str_two = upto20[(int)_amount2];
    }
    else
    {
        int tens = _amount2 / 10;
        int ones = _amount2 - (tens * 10);
        str_two = ten_ninety[tens] + upto20[ones];
    }

    string ret_val = "$ " +str_one + " and " + str_two + " cents";
    system("pause");
    return ret_val;
};



void TextVersionOfNumber::setAmount(double _amount)
{
    amount = _amount;
};

这是测试人员档案（这是我老师提供的）

//  Chapter 12--  Assignment 14:  Check Writer
// This program can convert a dollar and cents amount given in 
// numerical form to a word description of the amount.
#include <iostream>
#include <iomanip>
#include <string>
#include <string.h>
using namespace std;

#include "TextVersionOfNumber.h"
// Assume a maximum amount of $10,000

int main()
{
    string date = "03/05/2016", payee = "Michael Wille";
    TextVersionOfNumber checkAmount;
    double testAmounts[] = { 0, .01, .25, 12, 12.45, 19, 19.02,
        19.45, 20, 20.45,
        34, 56.78, 100, 109, 119.78,
        450, 678.90, 1000, 1009.45, 1056,
        1234, 1567.98, 9999, 9999.99 };

    for (int i = 0; i < sizeof(testAmounts) / sizeof(double); i++)
    {
        double an_amount = testAmounts[i];
        checkAmount.setAmount(an_amount);
        cout << setprecision(2) << fixed;
        cout << setw(60) << right;
        cout << "Date: " << date << endl;
        cout << "Pay to the order of:  " << payee << "\t\t\t";
        cout << "$" << an_amount << endl;
        cout << checkAmount.getTextVersionOfNumber() << endl;
        cout << "---------------------------------------------------------------------\n";
    }
    system("pause");
    return 0;
}

Answer 1

  else
    {
        int tens = _amount1 / 10;
        int ones = _amount1 - (tens * 10);
        str_one = ten_ninety[tens] + upto20[ones];
    }

如果amount = 100，则tens将等于10，您将其用作10个元素数组的引用，这些元素超出数组范围。你的代码可以工作＆lt; 100，但一旦它达到一百，它将不再起作用。

将数值转换为字符串元素的问题

1 个答案: