Question

当我在文本框中输入任何内容时，它不会显示任何内容。如果我硬编码$searchTerm='a';

，search.php会显示所有记录

可能这是我缺少的jQuery中的东西。

<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>test</title>
  <link rel="stylesheet" href="//code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css">
  <script src="//code.jquery.com/jquery-1.10.2.js"></script>
  <script src="//code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
  <script>
  $(function() {
    $( "#skills" ).autocomplete({
      source: 'search.php'
    });
  });
  </script>
</head>
<body>

<div class="ui-widget">
  <label for="skills">skills: </label>
  <input id="skills">
</div>
</body>
</html>

我的PHP（search.php）页面是：

 //get search term
        $searchTerm = $_GET['term'];

        //get matched data from skills table
        $query = $db->query("SELECT * FROM skills WHERE skill LIKE '%".$searchTerm."%' ORDER BY skill ASC");
        while ($row = $query->fetch_assoc()) {
            $data[] = $row['skill'];
        }

        //return json data
        echo json_encode($data);

Json

["A A EDU","A T Still","A.B.I. ","Aani", "Zane"]

Chrome调试

Answer 1

我无法看到发送params（数据）给您的服务器调用。

像这样（但如果这项工作，我还没对）：

$(function() {
   $( "#skills" ).autocomplete({
      source: 'search.php',
      data: { 
         'term' : $('#skills').val()
      },
      type: "GET"
   });
});

我更喜欢使用插件来执行此操作，在AJAX方法中可以将结果设置为在字段中列出。像这样：

$('#field_auto_complete').autocomplete({
    lookup: function (query, done) {
        $.ajax({
            url: "form.php",
            dataType: "json",
            data: { 
                    term     : query 
            },
            type: "GET", //you can change to POST if u need
            success: function( response ){
                var result = {
                    suggestions: response.results
                };
                done(result);   
            },
            error: function(XMLHttpRequest, textStatus, errorThrown) { 
                $.redirect('../error');
            }
        });
    },
    onSelect: function (suggestion) {
        id_ofselected = suggestion.data; //set a var with selected object
    }
});

在Php Side你有这样的代码：

$digits = $_GET['term'];

$query = $db->query(SELECT name AS `value`, id AS `data` 
          FROM table 
          WHERE name LIKE '$digits%'");

while ($row = $query->fetch_assoc()) {
    $data[] = $row['skill'];
}

if(isset($data[0])){
    echo json_encode(array( 'results' => $cons ));
}else{
    echo json_encode(array( 'results' => array());  
}

我使用Autocomplete Jquery插件。见[链接]（https://github.com/devbridge/jQuery-Autocomplete）！

Answer 2

{
    source: function( request, response ) {
      $.getJSON( "search.php", {
        term: extractLast( request.term )
      }, response );
    }

自动完成不起作用 - PHP - Mysql - jQuery

2 个答案: