我想列出所有自定义数据库:
SELECT `SCHEMA_NAME` AS 'Database',
`DEFAULT_CHARACTER_SET_NAME` AS 'Character Set',
`DEFAULT_COLLATION_NAME` AS 'Collation'
FROM `information_schema`.`SCHEMATA`
WHERE `SCHEMA_NAME` NOT IN ('information_schema','mysql','performance_schema')
ORDER BY `SCHEMA_NAME` ASC
但我想在每个数据库中包含表的数量:
SELECT `TABLE_SCHEMA`, COUNT(*)
FROM `information_schema`.`TABLES`
WHERE `TABLE_SCHEMA` NOT IN ('information_schema','mysql','performance_schema')
GROUP BY `TABLE_SCHEMA`
...在一张表中:
[
0 => [ 'Database'=>'customDb1', ..., 'Table Count'=>3 ],
1 => [ 'Database'=>'customDb2', ..., 'Table Count'=>8 ],
2 => [ 'Database'=>'customDb3', ..., 'Table Count'=>0 ]
]
我知道运行第一个查询,在PHP中循环遍历每个数据库,并运行第二个查询的效率远远低于使用表格JOIN
之类的东西,但我只是没有抓住{ {1}}语法。 Lynda tutorial我正在通过语言的这个相当(可能)复杂的部分进行调整,而我尝试的所有内容都会引发错误或错误结果。
我确信这是开发人员创建MySQL数据库接口的常见查询。如何使用仅 MySQL查询将表计数添加到我的数据库列表中?
答案 0 :(得分:3)
试试这个:
SELECT s.`SCHEMA_NAME` AS 'Database',
s.`DEFAULT_CHARACTER_SET_NAME` AS 'Character Set',
s.`DEFAULT_COLLATION_NAME` AS 'Collation',
COALESCE(COUNT(t.`TABLE_SCHEMA`),0) as table_cnt
FROM `information_schema`.`SCHEMATA` s
LEFT JOIN `information_schema`.`TABLES` t
ON(s.`SCHEMA_NAME` = t.`TABLE_SCHEMA`)
WHERE s.`SCHEMA_NAME` NOT IN ('information_schema','mysql','performance_schema')
GROUP BY s.`SCHEMA_NAME`
ORDER BY s.`SCHEMA_NAME` ASC