Question

我希望通过在SQL server中声明月份和年份来获取所有日期。

任何人都可以分享简单的SQL代码来获取它。

例如：

DECLARE @month AS INT = 5
DECLARE @Year AS INT = 2016
SELECT * from Something

我已尝试过以下内容，

DECLARE @month TINYINT=5

;WITH CTE_Days AS (
    SELECT DATEADD(
               MONTH,
               @month,
               DATEADD(
                   MONTH,
                   -MONTH(GETDATE()),
                   DATEADD(
                       DAY,
                       -DAY(GETDATE()) + 1,
                       CAST(FLOOR(CAST(GETDATE() AS FLOAT)) AS DATETIME)
                   )
               )
           ) Dates
    UNION ALL
    SELECT DATEADD(DAY, 1, Dates)
    FROM   CTE_Days
    WHERE  Dates < DATEADD(
               DAY,
               -1,
               DATEADD(
                   MONTH,
                   1,
                   DATEADD(
                       MONTH,
                       @month,
                       DATEADD(
                           MONTH,
                           -MONTH(GETDATE()),
                           DATEADD(
                               DAY,
                               -DAY(GETDATE()) + 1,
                               CAST(FLOOR(CAST(GETDATE() AS FLOAT)) AS DATETIME)
                           )
                       )
                   )
               )
           )
)
SELECT Dates
FROM   CTE_Days

但我正在寻找简单的解决方案，减少线条和简短的回答

Answer 1

你只能通过宣布月份来获得所有的日子，因为闰年你也需要添加年份：

DECLARE @date DATE = getdate()

;WITH N(N)AS 
(SELECT 1 FROM(VALUES(1),(1),(1),(1),(1),(1))M(N)),
tally(N)AS(SELECT ROW_NUMBER()OVER(ORDER BY N.N)FROM N,N a)
SELECT top(day(EOMONTH(@date)))
  N day,
  dateadd(d,N-1, @date) date
FROM tally

另一种不同的解决方案（由t @ clausen撰写）：

DECLARE @month AS INT = 5
DECLARE @Year AS INT = 2016

;WITH N(N)AS 
(SELECT 1 FROM(VALUES(1),(1),(1),(1),(1),(1))M(N)),
tally(N)AS(SELECT ROW_NUMBER()OVER(ORDER BY N.N)FROM N,N a)
SELECT N day,datefromparts(@year,@month,N) date FROM tally
WHERE N <= day(EOMONTH(datefromparts(@year,@month,1)))

Answer 2

与t-clausen相同，但更紧凑：

double

Answer 3

如果您有日期/时间列，请使用month()功能：

select t.*
from t
where month(datecol) = 5;

Answer 4

DECLARE @MonthNo TINYINT = 03 -- set your month
    ,@WOYEAR SMALLINT = 2018; -- set your year

IF OBJECT_ID('TEMPDB..#TMP') IS NOT NULL
    DROP TABLE #TMP

DECLARE @START_DATE DATETIME
    ,@END_DATE DATETIME
    ,@CUR_DATE DATETIME

SET @START_DATE = DATEADD(month, @MonthNo - 1, DATEADD(year, @WOYEAR - 1900, 0))
SET @END_DATE = DATEADD(day, - 1, DATEADD(month, @MonthNo, DATEADD(year, @WOYEAR - 1900, 0)))
SET @CUR_DATE = @START_DATE

CREATE TABLE #TMP (
    WEEKDAY VARCHAR(10)
    ,DATE INT
    ,MONTH VARCHAR(10)
    ,YEAR INT
    ,dates VARCHAR(25)
    )

WHILE @CUR_DATE <= @END_DATE
BEGIN
    INSERT INTO #TMP
    SELECT DATENAME(DW, @CUR_DATE)
        ,DATEPART(DAY, @CUR_DATE)
        ,DATENAME(MONTH, @CUR_DATE)
        ,DATEPART(YEAR, @CUR_DATE)
        ,REPLACE(CONVERT(VARCHAR(9), @CUR_DATE, 6), ' ', '-')

    SET @CUR_DATE = DATEADD(DD, 1, @CUR_DATE)
END

SELECT *
FROM #TMP

Answer 5

DECLARE @Today DATE= GETDATE() ,
@StartOfMonth DATE ,
@EndOfMonth DATE;

DECLARE @DateList TABLE ( DateLabel VARCHAR(10) );
SET @EndOfMonth = EOMONTH(GETDATE());
SET @StartOfMonth = DATEFROMPARTS(YEAR(@Today), MONTH(@Today), 1);

WHILE @StartOfMonth <= @EndOfMonth
BEGIN
   INSERT  INTO @DateList
   VALUES  ( @StartOfMonth );
   SET @StartOfMonth = DATEADD(DAY, 1, @StartOfMonth);
END;

SELECT  DateLabel
FROM    @DateList;

Answer 6

您可以使用以下查询获取一个月的所有日期。

declare @month int, @year int
set @month = 2
set @year = 2008

SELECT
CAST(CAST(@year AS VARCHAR) + '-' + CAST(@Month AS VARCHAR) + '-01' AS DATETIME) + Number
FROM master..spt_values
WHERE type = 'P'
AND
(CAST(CAST(@year AS VARCHAR) + '-' + CAST(@Month AS VARCHAR) + '-01' AS DATETIME) + Number )
<
DATEADD(mm,1,CAST(CAST(@year AS VARCHAR) + '-' + CAST(@Month AS VARCHAR) + '-01' AS DATETIME) )

希望这会对您有所帮助。

Answer 7

WHERE Dates LIKE '2018-12%'

在日期时间或时间戳中，它变为“年-月”，因此这将拉取与12月匹配的2018年的所有内容。您可以修改它以使用您的变量。

@month = 12;
@year = 2018;
@searchQuery = @year + @month + '%';

WHERE Dates LIKE @searchQuery

Answer 8

另一个基于CTE的版本

(n_points-1,n_points-1)

Answer 9

小的修改。 @ t-clausen.dk给出的查询只有在每月的第一天运行时才会给出正确的结果。只需一点改动，它就很棒。

DECLARE @date DATE = getdate()

;WITH N(N)AS 
(SELECT 1 FROM(VALUES(1),(1),(1),(1),(1),(1))M(N)),
tally(N)AS(SELECT ROW_NUMBER()OVER(ORDER BY N.N)FROM N,N a)


SELECT top(day(EOMONTH(@date)))
 N day,
 DATEFROMPARTS(year(@date),month(@date), n) date
FROM tally

顺便说一句t-clausen.dk。我想不出更简单的方法

Answer 10

这是一个查询：

DECLARE @ReportDate VARCHAR(20)='2019-02-10'

DECLARE @LastDay INT =DAY(EOMONTH(@ReportDate))

DECLARE @DayStart INT=01

CREATE TABLE #TEMPMonth ([MDay] VARCHAR(20))

WHILE @LastDay>=@DayStart

BEGIN
    
INSERT INTO #TEMPMonth 
    
SELECT CAST(CAST(YEAR(@ReportDate)AS VARCHAR)+'-'+CAST(MONTH(@ReportDate)AS VARCHAR)+'-'+CAST(@DayStart AS VARCHAR) AS DATE)
    SET @DayStart+=1

END

SELECT * FROM #TEMPMonth

DROP TABLE #TEMPMonth

Answer 11

CREATE FUNCTION fn_GetMonthlyDates
(
  @ProcessDate smalldatetime
)
RETURNS @LOAN TABLE 
(
 ProcessDate    smalldatetime
)
AS
BEGIN
    DECLARE 
        @Today DATE= @ProcessDate,
        @StartOfMonth DATE ,
        @EndOfMonth DATE;

    DECLARE @DateList TABLE (DateLabel VARCHAR(10) );
    SET @EndOfMonth = EOMONTH(@Today);
    SET @StartOfMonth = DATEFROMPARTS(YEAR(@Today), MONTH(@Today), 1);

    WHILE @StartOfMonth <= @EndOfMonth
    BEGIN
       INSERT  INTO @DateList
       VALUES  (@StartOfMonth );
       SET @StartOfMonth = DATEADD(DAY, 1, @StartOfMonth);
    END;

    INSERT INTO @LOAN(ProcessDate)
    SELECT  DateLabel
    FROM    @DateList; 

RETURN
END

Answer 12

这是另一种方式，但结果相同。

declare @year int=2021,@month int=3

select  DATEADD(dd,a.n-1,datefromparts(@year,@month,1)) 
from    (
         select top 31 ROW_NUMBER() over (order by a.object_id) as n
         from   sys.all_objects a
      ) a where DATEPART(mm,DATEADD(dd,a.n-1,datefromparts(@year,@month,1)))=3

获取SQL Server中给定月份和年份的所有日期

12 个答案: