Question

我使用vs2015，webapi网络服务和xamarin.Android

我创建了一个包含2个项目的解决方案

1-项目是web Api 2-是xamarin.android项目

在Web API项目中我有一个Url（http://localhost:27635/api/books/1/details）这回复了这本书的详细信息

{"query":{"Title":"Midnight Rain","Genre":"Fantasy","PublishDate":"2000-12-16T00:00:00","Description":"A former architect battles an evil sorceress.","Price":14.95,"Author":"Ralls, Kim"}}
"}

并在xamarin项目中：我使用此代码来使用web api项目公共类MainActivity：活动 {

    protected override void OnCreate(Bundle bundle)
    {
        base.OnCreate(bundle);

        // Set our view from the "main" layout resource
        SetContentView(Resource.Layout.Main);

   :
        Button button = FindViewById<Button>(Resource.Id.getWeatherButton);

        // When the user clicks the button ...
        button.Click += async (sender, e) => {

            // Get the latitude and longitude entered by the user and create a query.
            string url = "http://localhost:8080/api/books/1/details";
            //string url = "http://169.254.129.9/api/books/1/details";

            // Fetch the information asynchronously, 
            // parse the results, then update the screen:
            JsonValue json = await FetchWeatherAsync(url);
            ParseAndDisplay(json);
        };
    }
    // Gets data from the passed URL.
    private async Task<JsonValue> FetchWeatherAsync(string url)
    {
        // Create an HTTP web request using the URL:
        HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(new Uri(url));
        request.ContentType = "application/json";
        request.Method = "GET";

        // Send the request to the server and wait for the response:
        using (WebResponse response = await request.GetResponseAsync())
        {
            // Get a stream representation of the HTTP web response:
            using (Stream stream = response.GetResponseStream())
            {
                // Use this stream to build a JSON document object:


                   JsonValue jsonDoc = await Task.Run(() => JsonObject.Load(stream));
                    Console.Out.WriteLine("Response: {0}", jsonDoc.ToString());

                    // Return the JSON document:
                    return jsonDoc;

                }
            }
        }
        // Parse the weather data, then write temperature, humidity, 
private void ParseAndDisplay(JsonValue json)
        {
            TextView location = FindViewById<TextView>(Resource.Id.locationText);


            JsonValue weatherResults = json["query"];


            location.Text = weatherResults["Title"];

        }
    }

当我使用我的本地webapi项目时，下面的代码将不会被执行，并且本地webservice无法连接到Android模拟器以从Web服务获取数据，并且给我一个错误

using (Stream stream = response.GetResponseStream())
{
 // Use this stream to build a JSON document object:
 JsonValue jsonDoc = await Task.Run(() => JsonObject.Load(stream));
Console.Out.WriteLine("Response: {0}", jsonDoc.ToString());
// Return the JSON document:
return jsonDoc;
}

但是，当我使用外部网络api工作正常时

本地webservice无法连接到Android模拟器

0 个答案: